Other comment is wrong
2.5 g 1 mol/18.02 g (-285.83) kJ/mol
The amount of energy generated from freezing 2.5g of water can be calculated using the specific heat capacity of water and the heat of fusion for water. The energy released would be equal to the heat of fusion of water (334 J/g) multiplied by the mass of water (2.5g). By multiplying these values, you can determine the total energy released during the freezing process.
2.5 g 1 mol/18.02 g (-285.83) kJ/mol
The freezing cannot be stopped; only the freezing temperature is lowered adding salts.
2.5 g 1 mol/18.02 g (-285.83) kJ/mol
2.5 g 1 mol/18.02 g (-285.83) kJ/mol
The amount of energy generated from freezing 2.5g of water can be calculated using the specific heat capacity of water and the heat of fusion for water. The energy released would be equal to the heat of fusion of water (334 J/g) multiplied by the mass of water (2.5g). By multiplying these values, you can determine the total energy released during the freezing process.
2.5 g 1 mol/18.02 g (-285.83) kJ/mol
To calculate the energy released when freezing 2.5 g of water, we use the heat of fusion for water, which is approximately 334 J/g. Multiplying the mass of water by the heat of fusion, we get: Energy = 2.5 g × 334 J/g = 835 J. Thus, freezing 2.5 g of water releases about 835 joules of energy.
Electric energy generated from a water source is typically known as hydroelectric energy.
Water freezing is not considered energy itself, but rather a process that releases energy. When water freezes, it releases heat energy into its surroundings. The process of freezing involves the removal of energy from the water molecules, causing them to slow down and form a solid structure.
is goes throught a cycle that makes energy and then that is how it is generated
physical energy
To decrease the freezing point of water by 2.5 degrees Celsius, you would need to dissolve approximately 37.5 grams of sugar in 300 grams of water. This is calculated based on the colligative property that states freezing point depression is directly proportional to the molality of the solute in the solution.
The freezing point of solution is always less than that of the freezing point of the pure solvent. The freezing point of pure water is 0 (zero) degree celsius. The freezing point of the water decreases with the increase in the sugar concentration. for ex. a 10 grams of sugar when dissolved in 100 grams of water, the freezing point depression of -0.56 degree Celsius A 10 molal sucrose will bring about the depression in freezing point of water to about -20 degree celsius
Energy generated from moving water.
The freezing cannot be stopped; only the freezing temperature is lowered adding salts.
When water freezes, thermal energy is released from the water as it changes from a liquid to a solid. This released energy is responsible for lowering the temperature of the water to its freezing point and then further to form ice.