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How much heat is required to melt 2 kg of gold?
The specific heat capacity of gold is 0.129 J/g°C. The heat required to melt 2 kg of gold can be calculated by using the formula Q = m * c * ΔT, where Q is the heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Assuming gold melts at 1064°C and starting from room temperature (20°C), the total heat required to melt 2 kg of gold is approximately 3.6 x 10^5 Joules.
How much energy is needed to melt 2 kg of aluminum?
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How much energy is required to melt 2 kg of aluminum Use the table below and this equation Q mLfusion?
Using the specific latent heat of fusion for aluminum (397 kJ/kg), we can calculate the energy required to melt 2 kg of aluminum: Q = m * L Q = 2 kg * 397 kJ/kg Q = 794 kJ Therefore, it would require 794 kJ of energy to melt 2 kg of aluminum.
Energy required to melt a solid into a liquid?
The energy required to melt a solid into a liquid is known as the heat of fusion. This energy is needed to overcome the intermolecular forces holding the solid together and break down its crystal structure, allowing the particles to move freely in the liquid state. The amount of heat of fusion varies depending on the substance.
How is the H fusion used to calculate the mass of solid that 1kJ of energy will melt?
The enthalpy of fusion of a substance (H fusion) tells us how much energy is required to melt one gram of the substance. By dividing the energy input (1 kJ) by the enthalpy of fusion, you can calculate the mass of the substance that the energy will melt. It's a simple ratio: mass = energy input (kJ) / enthalpy of fusion (kJ/g).
How much energy is required to melt 2kg of gold?
To melt 2 kg of gold, it would require approximately 66,190 Joules per gram. Therefore, for 2 kg of gold, the total energy required would be around 132,380,000 Joules.
How much energy is required to melt 1.5 kg of gold?
The heat of fusion for gold is 64.4 kJ/mol. To convert this to energy required to melt 1.5 kg of gold, we need to calculate the number of moles in 1.5 kg of gold (1.5 kg of gold is approximately 0.047 moles). Then, the energy required would be approximately 3.03 kJ.
How much energy is required to melt 1.5 kg gold?
The specific heat of gold is 0.129 J/g°C, and its melting point is 1064°C. The energy required to melt 1.5 kg of gold can be calculated using the formula: Energy = mass * specific heat * temperature change. So, the energy required would be approximately 2.3 x 10^6 Joules.
How much energy is needed to melt 2kg of gold?
It takes approximately 64,000 Joules of energy to melt 1kg of gold. Therefore, to melt 2kg of gold, you would need around 128,000 Joules of energy.
How much ergy is required to melt 2 kg of gold?
The specific heat capacity of gold is 0.128 J/g°C, and the heat of fusion of gold is 63 J/g. To calculate the energy required to melt 2 kg of gold, you would first need to convert the mass to grams (2000 g). The energy required would be the sum of the energy needed to raise the temperature from the melting point to the melting point and the energy needed for the phase change.
What is the measurement of how much heat energy is required for a substance to melt?
The measurement of how much heat energy is required for a substance to melt is called the heat of fusion. It is the amount of energy required to change a substance from a solid to a liquid at its melting point.
How much energy is required to melt 1.5 of lead?
36.8 kj
How much energy is required to melt 10g of ice?
The energy required to melt ice is known as the heat of fusion, which is about 334 joules per gram. Therefore, it would take approximately 3340 joules of energy to melt 10g of ice.
How much energy is required to melt to kilograms of copper?
The energy required to melt 1 kg of copper at its melting point of about 1084°C is approximately 205 kJ. Therefore, to melt 2 kg of copper, you would need around 410 kJ of energy.
How much energy is required to melt 56g?
The energy required to melt a substance can be calculated using the formula: Energy = mass x heat of fusion. For water, the heat of fusion is 334 J/g. Therefore, the energy required to melt 56g of water would be 56g x 334 J/g = 18,704 J.
How much energy required for J meson to melt?
J mesons are subatomic particles that do not experience a melting phase transition like larger particles or materials. As such, they do not require energy to melt as they do not solidify.
How much energy would be required to melt 32.0 g of ice?
The amount of energy required to melt ice can be calculated using the equation: energy = mass of ice * heat of fusion. The heat of fusion for ice is 334 J/g, so for 32.0 g of ice, the energy required would be 32.0 g * 334 J/g = 10,688 J.
