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How much energy is released when 65.8g of water freezes?

Anonymous

∙ 12y ago

Updated: 5/30/2024

Hfus of water is 333.55

(333.55j/g)(65.8g)=21947.59J

21947.59/1000= 21.947kJ

I think

Wiki User

∙ 12y ago

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What is the mass of 3.34 moll of gold atoms?

To find the mass of 3.34 moles of gold atoms, you need to multiply the number of moles by the molar mass of gold. The molar mass of gold is 196.97 g/mol. Therefore, the mass of 3.34 moles of gold atoms is 3.34 moles * 196.97 g/mol = 658.5 grams.

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What is the mass of 3.34 moll of gold atoms?

To find the mass of 3.34 moles of gold atoms, you need to multiply the number of moles by the molar mass of gold. The molar mass of gold is 196.97 g/mol. Therefore, the mass of 3.34 moles of gold atoms is 3.34 moles * 196.97 g/mol = 658.5 grams.

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