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Why do you need to add distilled water in a potassium iodate solution in a volumetric flask until it reaches 250ml?
To dilute it to a certain concentration given in moles. It is best to transfer it to a beaker first to make sure it dissolves. The 250ml figure is dependent on how much of the solution that you need
How do you prepare 0.25N sulphuric acid from 2N sulphuric acid?
To prepare 0.25N sulphuric acid from 2N sulphuric acid, you can dilute the 2N solution by adding 7 parts of water to 1 part of the 2N solution. This will result in a final 0.25N sulphuric acid solution.
What volume of 12M HCl solution is needed to prepare 250 mL of 0.100M solution?
To find the volume needed, you can use the formula: M1V1 = M2V2. Here, M1 = 12M (initial concentration), V1 = volume of 12M HCl solution needed, M2 = 0.100M (final concentration), and V2 = 250 mL. Rearranging the formula, V1 = (M2 * V2) / M1 = (0.100M * 250mL) / 12M = 2.08 mL. Therefore, you will need 2.08 mL of the 12M HCl solution to prepare 250 mL of 0.100M solution.
Given a stock solution of 0.5 M NaCl describe how you would prepare 100ml of 2M of the solution of NaCl?
You need to know the gram molecular mass (in this instance, since sodium chloride is an ionically bonded compound and does not have moles in the strictest sense, more properly the gram formula unit mass) of sodium chloride, which is 58.44. The number of grams required may be calculated as set forth below. By definition, a 0.05M solution contains 0.05 moles of solute (sodium chloride in this instance) per liter of solution, and there are 1000 ml per liter. Therefore, the number of moles required for the specified amount of 0.05M solution is 0.05(125/1000) or 0.00625. The amount of sodium chloride required is therefore 0.00625(58.44) or 0.4 grams, to the justified number of significant digits, which is limited by the fact that the molar concentration stated has only one significant digit. If 0.05 were interpreted as having at least three significant digits, then the answer would be 0.3652 grams.
How many grams of calcium chloride will you add to 250mL of water to make a 0.236 M solution?
Molarity is moles of solute / liters of solvent. Plugging in the data: 0.236M = x / 0.250L; x = (0.236M)(0.250L) = 0.0590 moles of CaCl2. The molecular weight of CaCl2 is 40.1 + 2(35.5) = 111.1 g / mole. The mass of CaCl2 = (MW)(moles) = (111.1g/mole)(0.0590moles) = 6.55g
Why do you need to add distilled water in a potassium iodate solution in a volumetric flask until it reaches 250ml?
To dilute it to a certain concentration given in moles. It is best to transfer it to a beaker first to make sure it dissolves. The 250ml figure is dependent on how much of the solution that you need
How many moles of sodium chloride are there in 250ml of a 1.20 m sodium chloride solution?
To find the number of moles of sodium chloride in a 250 mL solution with a concentration of 1.20 m, you can use the formula: moles = concentration (mol/L) × volume (L). First, convert 250 mL to liters, which is 0.250 L. Then, multiply: 1.20 mol/L × 0.250 L = 0.30 moles of sodium chloride.
How do you prepare 0.25N sulphuric acid from 2N sulphuric acid?
To prepare 0.25N sulphuric acid from 2N sulphuric acid, you can dilute the 2N solution by adding 7 parts of water to 1 part of the 2N solution. This will result in a final 0.25N sulphuric acid solution.
What volume of 12M HCl solution is needed to prepare 250 mL of 0.100M solution?
To find the volume needed, you can use the formula: M1V1 = M2V2. Here, M1 = 12M (initial concentration), V1 = volume of 12M HCl solution needed, M2 = 0.100M (final concentration), and V2 = 250 mL. Rearranging the formula, V1 = (M2 * V2) / M1 = (0.100M * 250mL) / 12M = 2.08 mL. Therefore, you will need 2.08 mL of the 12M HCl solution to prepare 250 mL of 0.100M solution.
If you have 250 milliliters of a solution and you need to have the solution in cubic centimeters How do you convert this?
1cc (cubic centimeter) and 1mL (milliliter) are the same volume. So, 250mL is the same as 250cc
How do you prepare 250ml saturated solution of sodium thiosulphate?
To prepare a 250 ml saturated solution of sodium thiosulphate, start by adding sodium thiosulphate (Na2S2O3·5H2O) to a clean container, gradually mixing it with distilled water until no more solid dissolves and the solution reaches saturation. Typically, this requires adding approximately 80 grams of sodium thiosulphate to the water. Stir the mixture thoroughly and allow it to settle for any undissolved solids to settle at the bottom. Finally, transfer the clear solution to a volumetric flask and make up the volume to 250 ml with distilled water.
How much is 250 ml of milk?
250ml of milk = 250ml of milk 250ml of milk = roughly 256g of milk 250ml of milk = roughly 1 cup plus 2/3 of a tablespoon
Is there artificial sweetener in Gatorade?
G2 Gatorade (ORANGE) 591ml bottle contains the following:Water, Liquid Sugar, Natural Flavors, Citric Acid, salt, Sodium Citrate, Monopotassium Phosphate, SUCRALOSE (47mg/250ml), ACESULFAME POTASSIUM (9mg/250ml), Colour.I have the bottle sitting right in front of me so I can yes, G2 Gatorade ORANGE has artificial sweetners in it, Acesulfame potassium (Sunett, Sweet One) and Sucralose (Splenda).
How many 250ml in 1.89 liter?
There are 7.56 250ml units in 1.89 liters.
Calculate the volume of solution needed to dissolve 0.25 moles NaCl to make a 3.0M solution?
3.00 M, or 3 moles per (L) "liter" calls for having 3 moles per liter of the solution. The question asks how many moles must be in 250ml of a solution that has 3 moles per Liter. You must ask yourself what percent of 1 Liter is 250mls? Since there are a thousand ml in one liter, (1000ml=1L), then 250ml is exactly 25% of a Liter, or .25L. So, 250ml can only hold 25% of the 3.00 Molarity. Meaning that you multiply 3 x .25 and get .75 moles.
Given a stock solution of 0.5 M NaCl describe how you would prepare 100ml of 2M of the solution of NaCl?
You need to know the gram molecular mass (in this instance, since sodium chloride is an ionically bonded compound and does not have moles in the strictest sense, more properly the gram formula unit mass) of sodium chloride, which is 58.44. The number of grams required may be calculated as set forth below. By definition, a 0.05M solution contains 0.05 moles of solute (sodium chloride in this instance) per liter of solution, and there are 1000 ml per liter. Therefore, the number of moles required for the specified amount of 0.05M solution is 0.05(125/1000) or 0.00625. The amount of sodium chloride required is therefore 0.00625(58.44) or 0.4 grams, to the justified number of significant digits, which is limited by the fact that the molar concentration stated has only one significant digit. If 0.05 were interpreted as having at least three significant digits, then the answer would be 0.3652 grams.
Is 1 mesuring cup 250ml?
It varies from 226 to 250ml.
