111.72
To dilute it to a certain concentration given in moles. It is best to transfer it to a beaker first to make sure it dissolves. The 250ml figure is dependent on how much of the solution that you need
To prepare 0.25N sulphuric acid from 2N sulphuric acid, you can dilute the 2N solution by adding 7 parts of water to 1 part of the 2N solution. This will result in a final 0.25N sulphuric acid solution.
To find the volume needed, you can use the formula: M1V1 = M2V2. Here, M1 = 12M (initial concentration), V1 = volume of 12M HCl solution needed, M2 = 0.100M (final concentration), and V2 = 250 mL. Rearranging the formula, V1 = (M2 * V2) / M1 = (0.100M * 250mL) / 12M = 2.08 mL. Therefore, you will need 2.08 mL of the 12M HCl solution to prepare 250 mL of 0.100M solution.
You need to know the gram molecular mass (in this instance, since sodium chloride is an ionically bonded compound and does not have moles in the strictest sense, more properly the gram formula unit mass) of sodium chloride, which is 58.44. The number of grams required may be calculated as set forth below. By definition, a 0.05M solution contains 0.05 moles of solute (sodium chloride in this instance) per liter of solution, and there are 1000 ml per liter. Therefore, the number of moles required for the specified amount of 0.05M solution is 0.05(125/1000) or 0.00625. The amount of sodium chloride required is therefore 0.00625(58.44) or 0.4 grams, to the justified number of significant digits, which is limited by the fact that the molar concentration stated has only one significant digit. If 0.05 were interpreted as having at least three significant digits, then the answer would be 0.3652 grams.
Molarity is moles of solute / liters of solvent. Plugging in the data: 0.236M = x / 0.250L; x = (0.236M)(0.250L) = 0.0590 moles of CaCl2. The molecular weight of CaCl2 is 40.1 + 2(35.5) = 111.1 g / mole. The mass of CaCl2 = (MW)(moles) = (111.1g/mole)(0.0590moles) = 6.55g
To dilute it to a certain concentration given in moles. It is best to transfer it to a beaker first to make sure it dissolves. The 250ml figure is dependent on how much of the solution that you need
To prepare 0.25N sulphuric acid from 2N sulphuric acid, you can dilute the 2N solution by adding 7 parts of water to 1 part of the 2N solution. This will result in a final 0.25N sulphuric acid solution.
To find the volume needed, you can use the formula: M1V1 = M2V2. Here, M1 = 12M (initial concentration), V1 = volume of 12M HCl solution needed, M2 = 0.100M (final concentration), and V2 = 250 mL. Rearranging the formula, V1 = (M2 * V2) / M1 = (0.100M * 250mL) / 12M = 2.08 mL. Therefore, you will need 2.08 mL of the 12M HCl solution to prepare 250 mL of 0.100M solution.
1cc (cubic centimeter) and 1mL (milliliter) are the same volume. So, 250mL is the same as 250cc
250ml of milk = 250ml of milk 250ml of milk = roughly 256g of milk 250ml of milk = roughly 1 cup plus 2/3 of a tablespoon
There are 7.56 250ml units in 1.89 liters.
G2 Gatorade (ORANGE) 591ml bottle contains the following:Water, Liquid Sugar, Natural Flavors, Citric Acid, salt, Sodium Citrate, Monopotassium Phosphate, SUCRALOSE (47mg/250ml), ACESULFAME POTASSIUM (9mg/250ml), Colour.I have the bottle sitting right in front of me so I can yes, G2 Gatorade ORANGE has artificial sweetners in it, Acesulfame potassium (Sunett, Sweet One) and Sucralose (Splenda).
3.00 M, or 3 moles per (L) "liter" calls for having 3 moles per liter of the solution. The question asks how many moles must be in 250ml of a solution that has 3 moles per Liter. You must ask yourself what percent of 1 Liter is 250mls? Since there are a thousand ml in one liter, (1000ml=1L), then 250ml is exactly 25% of a Liter, or .25L. So, 250ml can only hold 25% of the 3.00 Molarity. Meaning that you multiply 3 x .25 and get .75 moles.
You need to know the gram molecular mass (in this instance, since sodium chloride is an ionically bonded compound and does not have moles in the strictest sense, more properly the gram formula unit mass) of sodium chloride, which is 58.44. The number of grams required may be calculated as set forth below. By definition, a 0.05M solution contains 0.05 moles of solute (sodium chloride in this instance) per liter of solution, and there are 1000 ml per liter. Therefore, the number of moles required for the specified amount of 0.05M solution is 0.05(125/1000) or 0.00625. The amount of sodium chloride required is therefore 0.00625(58.44) or 0.4 grams, to the justified number of significant digits, which is limited by the fact that the molar concentration stated has only one significant digit. If 0.05 were interpreted as having at least three significant digits, then the answer would be 0.3652 grams.
0.4
It varies from 226 to 250ml.
Add to 250ml of pasteurised cream 15ml of lemon juice, stir to thicken. For a more sour taste simply add more juice