935ml
In 1 Litre solution there are:1.0 mole HCl (totally ionised into 1.0 mole H3O+ and 1.0 mole Cl-)and54 mole H2O (the remaining of 55)
0.9051 moles Mg per liter of solution. Molarity is the amount of moles per liter of solution. So just divide the number of grams of Mg by its molar mass then divide that by the number of liters
weigh out 365g of HCl pellets and dilute to 1 liter to prepare the 10N HCl solution. Reasons:N is short for NORMAL SOLUTIONS, The definition of a NORMAL SOLUTION is a solution that contains 1 gram equivalent weight (gEW) per liter solution. An equivalent weight is equal to the molecular weight divided by the valence (replaceable H ions). eg:1N NaCl = 58.5 g/L 1N HCl = 36.5 g/L 1N H2S04 = 49 g/L Problems involving normality are worked the same as those involving molarity but the valence must be considered: 1N HCL the MW= 36.5 the EW = 36.5 and 1N would be 36.5g/L 1N H2SO4 the MW = 98 the EW = 49 and 1N would be 49 g/L 1N H3PO4 the MW = 98 the EW = 32.7 and 1N would be 32.7 g/L so,u can weigh out 365g of HCl pellets and dilute to 1 liter to prepare the 10N HCl solution.
40 ml of NaOH contains 0.04 L * 3.5 M = 0.14 mole of NaOH Since NaOH donates 1 OH you will also have 0.14 mole of OH- in solution. This can be neutralised with an equal amount of H+. HCl can donate 1 H+, so you need an equal amount of H+ to neutralise the OH-. So you need 0.14 mole of the HCl. 55 ml has 0.14 mole HCl. So the molarity is: 0.14 mole / 0.055 L = 2.54 M
To calculate the number of molecules in 55 grams of sulfuric acid (H2SO4), you first need to determine the molar mass of sulfuric acid, which is 98.08 g/mol. Next, find the number of moles in 55 grams by dividing the mass by the molar mass. Finally, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
The concentration of pure water is 55 molar. In other words, 1 liter of water holds 55 moles of H2O
In 1 Litre solution there are:1.0 mole HCl (totally ionised into 1.0 mole H3O+ and 1.0 mole Cl-)and54 mole H2O (the remaining of 55)
0.9051 moles Mg per liter of solution. Molarity is the amount of moles per liter of solution. So just divide the number of grams of Mg by its molar mass then divide that by the number of liters
You don't. There's no such thing. There are about 55 moles of water per liter, so pure water is around 111 N at most.
weigh out 365g of HCl pellets and dilute to 1 liter to prepare the 10N HCl solution. Reasons:N is short for NORMAL SOLUTIONS, The definition of a NORMAL SOLUTION is a solution that contains 1 gram equivalent weight (gEW) per liter solution. An equivalent weight is equal to the molecular weight divided by the valence (replaceable H ions). eg:1N NaCl = 58.5 g/L 1N HCl = 36.5 g/L 1N H2S04 = 49 g/L Problems involving normality are worked the same as those involving molarity but the valence must be considered: 1N HCL the MW= 36.5 the EW = 36.5 and 1N would be 36.5g/L 1N H2SO4 the MW = 98 the EW = 49 and 1N would be 49 g/L 1N H3PO4 the MW = 98 the EW = 32.7 and 1N would be 32.7 g/L so,u can weigh out 365g of HCl pellets and dilute to 1 liter to prepare the 10N HCl solution.
That is 550 ml.
116.23 pints 1 liter = 2.11 pints 1 pint = 0.47 liter
40 ml of NaOH contains 0.04 L * 3.5 M = 0.14 mole of NaOH Since NaOH donates 1 OH you will also have 0.14 mole of OH- in solution. This can be neutralised with an equal amount of H+. HCl can donate 1 H+, so you need an equal amount of H+ to neutralise the OH-. So you need 0.14 mole of the HCl. 55 ml has 0.14 mole HCl. So the molarity is: 0.14 mole / 0.055 L = 2.54 M
A cubic decimeter and a liter have the same volume so 0.55 cubic decimeter = 0.55 liter.
55 gallons of deicing fluid costs about $800 U.S. So about $3.60 per liter.
55 litres
55