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None. A catalyst affects only the rate of reaction, and if the reaction is already at equilibrium, the net rate of the reaction is zero and remains so after a catalyst is added.

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How do solids affect equilibrium in a chemical reaction?

Solids do not affect the equilibrium of a chemical reaction because their concentration remains constant and does not change during the reaction. Only the concentrations of gases and dissolved substances in a reaction mixture can affect the equilibrium position.


Why does a numerically large Keq mean that the products are favored in an equilibrium system?

A numerically large equilibrium constant (Keq) indicates that the equilibrium lies far to the right, with more products present at equilibrium than reactants. This means that the forward reaction is favored, leading to a higher concentration of products compared to reactants in the equilibrium state.


If an equilibrium mixture is cooled what will be the effect on the intensity of the mixture color?

Cooling the equilibrium mixture will shift the equilibrium towards the side favoring the formation of the reactants (endothermic direction). The intensity of the mixture color could decrease if the reactants are colorless or have a lighter color compared to the products.


How does ethanol evaporation affect the efficiency of a chemical reaction?

Ethanol evaporation can affect the efficiency of a chemical reaction by changing the concentration of reactants and products in the reaction mixture. When ethanol evaporates, the volume of the reaction mixture decreases, leading to a higher concentration of the remaining components. This can potentially alter the reaction rate and equilibrium, impacting the overall efficiency of the reaction.


What is the difference between dissociation constant and equilibrium constant?

The dissociation constant describes the extent to which a compound breaks apart into its ions in a solution, specifically for weak acids or bases. The equilibrium constant, on the other hand, describes the ratio of product concentrations to reactant concentrations at equilibrium for a chemical reaction.

Related Questions

How would the equilibrium concentration of H½O be affected by removing H½ from the mixture?

If you remove H½ from the mixture, the equilibrium will shift to the left to compensate for the loss, meaning more H½O will dissociate to reform some of the missing H½. This will increase the concentration of H½O in an attempt to restore equilibrium.


How do solids affect equilibrium in a chemical reaction?

Solids do not affect the equilibrium of a chemical reaction because their concentration remains constant and does not change during the reaction. Only the concentrations of gases and dissolved substances in a reaction mixture can affect the equilibrium position.


What if kc expression is greater than 1 in chemistry?

If the Kc expression is greater than 1 in chemistry, it means that the concentration of products in the equilibrium mixture is higher than the concentration of reactants. This suggests that the reaction favors the formation of products at equilibrium.


What would happend if NO were added to n2(g) o2(g) 2no(g) at equilibrium?

If NO is added to the equilibrium mixture of N₂(g), O₂(g), and 2NO(g), the system will respond according to Le Chatelier's principle. The equilibrium will shift to the left, favoring the formation of reactants (N₂ and O₂) to counteract the increase in NO concentration. This shift will result in a decrease in the concentration of NO and an increase in the concentrations of N₂ and O₂ until a new equilibrium is established.


Why does a numerically large Keq mean that the products are favored in an equilibrium system?

A numerically large equilibrium constant (Keq) indicates that the equilibrium lies far to the right, with more products present at equilibrium than reactants. This means that the forward reaction is favored, leading to a higher concentration of products compared to reactants in the equilibrium state.


Can you write a sentence with the word catalyst?

"She added the catalyst to the mixture, and within seconds the reaction had started."


What is the concentration of HF in an equilibrium mixture established by adding mol each of H2 and F2 to a 1.00 L container at this temperature?

To determine the concentration of HF in an equilibrium mixture established by adding 1 mol each of H2 and F2 to a 1.00 L container, we first recognize that the reaction is (H_2 + F_2 \rightleftharpoons 2HF). Assuming the reaction goes to completion, we would initially have 1 mol of H2 and 1 mol of F2, which would produce 2 mol of HF. Since the total volume is 1.00 L, the concentration of HF at equilibrium would be 2 M. However, the actual equilibrium concentrations depend on the equilibrium constant (K) for this reaction at the given temperature, which would need to be known to provide a precise answer.


What will happen to the reaction mixture at equilibrium if the temperature is decreased?

If the temperature of a reaction mixture at equilibrium is decreased, the system will respond by favoring the exothermic direction of the reaction to produce heat. According to Le Chatelier's principle, this shift will result in an increase in the concentration of products if the forward reaction is exothermic, or an increase in reactants if the reverse reaction is exothermic. The overall effect will be a change in the equilibrium position to counteract the decrease in temperature.


If an equilibrium mixture is cooled what will be the effect on the intensity of the mixture color?

Cooling the equilibrium mixture will shift the equilibrium towards the side favoring the formation of the reactants (endothermic direction). The intensity of the mixture color could decrease if the reactants are colorless or have a lighter color compared to the products.


How does ethanol evaporation affect the efficiency of a chemical reaction?

Ethanol evaporation can affect the efficiency of a chemical reaction by changing the concentration of reactants and products in the reaction mixture. When ethanol evaporates, the volume of the reaction mixture decreases, leading to a higher concentration of the remaining components. This can potentially alter the reaction rate and equilibrium, impacting the overall efficiency of the reaction.


What does equilibrium and equilibrium mixture mean?

A quantity that characterizes the position of equilibrium for a reversible reaction; its magnitude is equal to the mass action expression at equilibrium. K varies with temperature.


How does an equilibrium reaction respond to the addiof extra reactant?

The concentration or activity of the product(s) will increase, and if there is at least one other reactant than the added one that is required for the completion of the reaction, the concentration of such an unadded reactant will decrease. (If there were no available unadded reactant, the reaction would not technically have been in equilibrium at the start, even though it may have reached a steady state that can persist for a long time in the absence of changed conditions.)