From my previous lab, i'm assuming it's the same, there are 4 tests: monosaccharaide, starch, lipid, and protein.
If a sugar cube is to be placed into the unknown solution and then tested by the 4 tests, there would be NO affect:
* Note: Some will think that placing a sugar cube into the solution will change the results of the monosaccharaide test, but there won't be. Remember, the monosaccharide only tests positive in the presence of a monosaccharaide, but sucrose is a DISACCHARIDE, so there will be no affect.
As for the other tests, they are indicators of starch, lipids, and proteins, again, nothing else. Therefore, sugar has no affect on the results whatsoever.
Which of the unknown colorless solutions is (are) acidic
The substance may be poisonous.
To deduce the concentration of a unknown solution from a known solution. Acid/base titration are common.
a higher concentration of OH- ions
Depending on what it is made of, it will just get hot and/or melt. This is not a good experiment since you will be exposing yourself to unknown fumes.
Which of the unknown colorless solutions is (are) acidic
To eliminate the possibility of hidden or unknown variables the scientist must a control experiment.
A responding variable
The answer to this question is ATM unknown
Because if you have any unknown factors you wont know how the experiment will react in any given situation.
A salt solution is what is commonly known as salt water.
There are a quite a few answers that fit this question. Gold is very ductile and is an excellent conductor of heat and electricity.
Ivan Pavlov's experiment demonstrated a significant new phenomenon, the conditioned response, that had previously been unknown to science.
If you place the cells in the unknown solution and it shrinks/shrivels up, then the unknown solution is hypertonic. That means it has higher concentrations of permeable ions than does the cell. If the cell ruptures/bursts, then the opposite is true. In that case, the unknown solution has a lower concentration of ions (hypotonic). If nothing happens to the cell and it maintains the original morphology, then the unknown solution is isotonic and has approximately the same ionic concentration as inside the cell. These observations are based on the principle of osmosis.
the studdies are unknown the studdies are unknown
The 'Variable' is the difference in the experiment that acts as the unknown factor. Results are drawn based on what the Variable does. -Vanack
The substance may be poisonous.