1s2 2s2 2p6 3s2
Magnesium Nitride is Mg3N2. What I think you do is draw it Mg N Mg N Mg and then draw 8 electrons around each Nitrogen so that Mg shares its 2 electrons with Nitrogen and Nitrogen's Pz electron is bumped down into the Px.
A condensed (or abbreviated) electron configuration is a way to draw an orbital diagram for a late electron. For this type of diagram the core electrons are replaced with the symbol for the noble gas nearest to the element you are describing. Brackets are put around this symbol and then the outer, valence electrons are described as usual.
The electron-dot structure for HBr would be:H:Br: (with two more pairs of dots on the top and bottom of Br)
Potassium (K) has an atomic number of 19. The noble gas electron configuration is [Ar]4s^1
There will be three electron shells with 2, 8 and 3 electrons (from 1st to 3rd shell).
Yes
1s^2 2s^2 2p^6
To see a drawing of the electron cloud configuration for gold (Au), use the link below.
1st shell - 2 electrons 2nd shell - 8 electrons 3rd shell - 4 electrons
to find the electron dot configuration of an element simply draw dots, symbolizing valance electrons, in a way that they are farthest from each other around the symbol of the element you are using.
Magnesium Nitride is Mg3N2. What I think you do is draw it Mg N Mg N Mg and then draw 8 electrons around each Nitrogen so that Mg shares its 2 electrons with Nitrogen and Nitrogen's Pz electron is bumped down into the Px.
How do you draw and electron cloud for 2Br and for Br2
internal configuration 8086
A condensed (or abbreviated) electron configuration is a way to draw an orbital diagram for a late electron. For this type of diagram the core electrons are replaced with the symbol for the noble gas nearest to the element you are describing. Brackets are put around this symbol and then the outer, valence electrons are described as usual.
The electron-dot structure for HBr would be:H:Br: (with two more pairs of dots on the top and bottom of Br)
Electron configurations show the energy levels, the orbitals and the number of electrons in each case. For example, the electron configuration of Na (at.no. 11) is 1s2 2s2 2p6 3s1. This shows that in energy level 1, there are 2 electrons in the s orbital. In the 2nd energy level, there are 2 electrons in the s orbital and 6 electrons in the p orbitals. etc. The orbital diagram would show essentially the same thing, but would include the spin of each electron, by showing up and down arrows. Cannot draw it here but if ^ represents up arrow and v represents down arrow, it would look something like ^v ^v ^v^v^v ^ 1s 2s 2p 3s
See an example at: http://education.jlab.org/qa/atom_model.html and note that thorium 232 has 90 protons, 142 neutrons and also 90 electrons; the electron configuration is [Rn] 6d27s2.