Sticking a piece of litmus paper into it would be the first step in my estimation. See if it's base or acidic. If it is strongly one or the other, don't touch it with bare hands.
You geek, why would you want to know that freak show
Because hydrochloric acid is a clear solution and potassium is a solid white powder the observation would be: a colourless, clear solution is add to a solid white powder which formed a solution and produced orderless, colourless gas. equation: 2H+(aq) +K2CO3(s) ---> 2K+(aq)+ CO2(g)+ H2O(l) NOTE: observations are what you actually see, therefore you would not be able to tell is the colourless gas was carbon dioxide or that water was present in the solution.
The most common one would be phenolphthalein which is colourless in acid and turns a pink-purple in base
The unknown substance would have to be a basic solution. At least more basic than the initial solution. The pH scale ranges from 0,Most acidic, to 14, Most Basic. If the pH of your solution increases when the unknown substance is added, then it would lead you to believe that the added substance is of a basic nature.
This is commonly used when describing liquids. "Clear" in this context means that you can see through the liquid, so if you put a penny (for example) in a cup of this liquid, you could still see the penny. "Colourless" would mean that the liquid was the same colour as water. Clear but not always colourless means that the liquid may have a tint (so it may be blueish or greenish or some other colour) but you can still see through it.
For an acid, the solution remains colourless or unchanged. For an alkali, it would turn fuschia.
from colourless(solution) to brown(solution)
You geek, why would you want to know that freak show
SO2 is less soluble in water... but solution of SO2 and CO2 will be colourless...
Lead will form Lead(II) Chloride in a HCl solution, but if exists a higher chloride ion concentration, it would form a soluble complex and a colourless solution.
Because hydrochloric acid is a clear solution and potassium is a solid white powder the observation would be: a colourless, clear solution is add to a solid white powder which formed a solution and produced orderless, colourless gas. equation: 2H+(aq) +K2CO3(s) ---> 2K+(aq)+ CO2(g)+ H2O(l) NOTE: observations are what you actually see, therefore you would not be able to tell is the colourless gas was carbon dioxide or that water was present in the solution.
You'd wind up with a solution of sodium sulfate and some water formed, along with any excess reactant. The solution would be clear and colorless.
Zinc salt will form complexes of sodium zincate which is colourless and a clear solution would be observed
The most common one would be phenolphthalein which is colourless in acid and turns a pink-purple in base
The unknown substance would have to be a basic solution. At least more basic than the initial solution. The pH scale ranges from 0,Most acidic, to 14, Most Basic. If the pH of your solution increases when the unknown substance is added, then it would lead you to believe that the added substance is of a basic nature.
Add universal indicator.
This is commonly used when describing liquids. "Clear" in this context means that you can see through the liquid, so if you put a penny (for example) in a cup of this liquid, you could still see the penny. "Colourless" would mean that the liquid was the same colour as water. Clear but not always colourless means that the liquid may have a tint (so it may be blueish or greenish or some other colour) but you can still see through it.