Add the acid to water.
Do NOT add water to the acid as it will boil and split acid everywhere.
Please say 100 mL of water in a beaker and slowly add sulphuric acid to it.
To change the molarities of the acid you need to do come calculations.
If you have say 50mL of 5M sulphurtic acid and you want to make it say 1M sulphuric acid.
Then use the eq'n moles = [conc] X vol(mL) / 1000
So
5M x 50mL / 1000 = 1M x vol(mL)/1000
Algebraically rearrange/.
vol(mL) = 5M x 50mL / 1M
NB THe '1000' cancel down.
vol(mL) = 250mL
In this case have 175 mL of water in a beaker, slowly add the 50mL (H2SO4), to avoid spitting. You will then have 225 mL. So then slowly add a further 25 mL of water to make the concentration 1M.
NB 225mL of sol'n will be of the wrong concentration, that is why you add a small final amount of water.
To dilute sulfuric acid, the acid should be added slowly to cold water with constant stirring to limit build-up of heat.
This acid will heat up very quickly, so when you add it to your cold water, you should place your container of water in a larger container filled with ice cold water and ice cubes to help keep the temperature down. If you let the temperature rise as you put it in the container, it will spray out of the container and if it comes in contact with your skin, it will burn you.
use the equation: NaVa=NbVb Where N is the normality and V is the volume. NOTE a is the original and b is what you're making. You would sove for Va
Concentrated sulfuric acid has sulfuric acid molecules where dilute sulfuric acid has sulfate ions and hydrogen ions. Water in the diluted solution acts as the ionization medium.
It depends on how diluted the dilute sulphuric acid is (i.e. its concentration).
You need to remove the water by evaporation.
When the concentration is considered, concentrated acid contains more molecules than the dilute acid. It is only one way to measure the strength. If we consider the reactivity with the absence of water and moisture, dilute sulfuric acid is more reactive than the concentrated acid.
use the equation: NaVa=NbVb Where N is the normality and V is the volume. NOTE a is the original and b is what you're making. You would sove for Va
Concentrated sulfuric acid has sulfuric acid molecules where dilute sulfuric acid has sulfate ions and hydrogen ions. Water in the diluted solution acts as the ionization medium.
It depends on how diluted the dilute sulphuric acid is (i.e. its concentration).
No, although "concentrated" sulfuric acid (essentially pure H2SO4) is less dissociated than dilute sulfuric acid, simply because there's no water around for it to dissociate in.
You need to remove the water by evaporation.
When the concentration is considered, concentrated acid contains more molecules than the dilute acid. It is only one way to measure the strength. If we consider the reactivity with the absence of water and moisture, dilute sulfuric acid is more reactive than the concentrated acid.
The most fizzing will come from the concentrated sulfuric acid, then dilute sulfuric acid, then the acetic acid.The amount of fizzing is due to the concentration of H+ in the solution, and concentrated sulfuric acid has the most H+ in solution. The dilute sulfuric acid has less (because it is dilute) and the acetic acid solution has the least of all because it is a weak acid rather than a strong acid.See the Related Questions for more information.
poure water on the concentrated acid
Dilute solutions of sulfuric acid conducts electricity because there are free ions, although concentrated sulfuric acid don't.
Pure water in solid state i.e. Ice
It depends on the concentration you want to achieve.
Dilute sulfuric acid has no effect on sugar. However, if the acid is sufficiently concentrated, the sugar decomposes to form carbon soot, which is black in color.