If 25.00ml of 50m naoh is used to titrate 26.25ml of hcl to the equivalence point what is the concentration of the hcl?

Answer 1

First balance the equation of the reaction:

NaOH + HCl ---> NaOH + H2O

The ratio of moles is 1:1

M1V1 = M2V2

(molarity1 x volume1) = (molarity2 x volume2)

M2 = M1V1 / V2

molarity2 = (molarity1 x volume1) / (volume2)

M of HCl = 50M x 0.025 litres / 0.02625 litres

= 47.6 M

Answer 2

Using the equation M1V1 = M2V2, where M1 is the concentration of NaOH, V1 is the volume of NaOH used, M2 is the concentration of HCl, and V2 is the volume of HCl used, we can calculate the concentration of HCl to be 48.48 M.