467.52 g NaCl
When sodium hydroxide is added to ferrous chloride, a precipitation reaction occurs. This results in the formation of insoluble ferrous hydroxide, which appears as a greenish precipitate. The balanced equation for this reaction is: FeCl2 + 2NaOH → Fe(OH)2 + 2NaCl.
The ionic equation for the reaction is: Fe^2+(aq) + CO3^2-(aq) -> FeCO3(s) and 2Na^+(aq) + 2Cl^-(aq) -> 2NaCl(aq).
Single Displacement
Iron(II) chloride (FeCl2) can be made by reacting iron with hydrochloric acid (HCl). The reaction produces FeCl2 and hydrogen gas (H2). Another method involves the reaction of iron oxide (FeO) with hydrochloric acid to form FeCl2 and water (H2O). FeCl2 can also be obtained by reducing iron(III) chloride (FeCl3) with hydrogen gas (H2) or with another reducing agent.
To balance the chemical equation FeCl2 + Na2CO3 → 2NaCl + FeCO3, you would need to adjust the coefficients in front of each compound. Start by balancing the metal atoms, then balance the non-metal atoms, and finally balance the charges. In this case, the balanced equation is 2FeCl2 + 3Na2CO3 → 6NaCl + FeCO3.
The mass of of iron(II) chloride (anhydrous) is 633,8 grams.
3 mole FeCl2 will react with 6 mole NaOH (stoechiometric mole ratio: 1 FeCl2 to 2 NaOH), so 3 mole FeCl2 (= 6 added -3 used) will be left over.
When sodium hydroxide is added to ferrous chloride, a precipitation reaction occurs. This results in the formation of insoluble ferrous hydroxide, which appears as a greenish precipitate. The balanced equation for this reaction is: FeCl2 + 2NaOH → Fe(OH)2 + 2NaCl.
To determine the grams of NaCl produced from 507 g of FeCl2, we first need to calculate the moles of FeCl2. The molar mass of FeCl2 is approximately 126.75 g/mol. Therefore, 507 g of FeCl2 is about 4.0 moles. According to the balanced equation, 1 mole of FeCl2 produces 2 moles of NaCl. Thus, 4.0 moles of FeCl2 will produce 8.0 moles of NaCl. The molar mass of NaCl is about 58.44 g/mol, so 8.0 moles of NaCl would weigh approximately 467.52 g.
The ionic equation for the reaction is: Fe^2+(aq) + CO3^2-(aq) -> FeCO3(s) and 2Na^+(aq) + 2Cl^-(aq) -> 2NaCl(aq).
Single Displacement
Iron Chloride + Sodium Hydroxide ------> Iron Hydroxide + Sodium Chloride Balanced reaction equations: FeCl3 + 3NaOH ------> Fe(OH)3 + 3NaCl or FeCl2 + 2NaOH ------> Fe(OH)2 + 2NaCl because iron can be either Iron(III)[Fe3+] or Iron(II)[Fe2+]
Iron(II) chloride (FeCl2) can be made by reacting iron with hydrochloric acid (HCl). The reaction produces FeCl2 and hydrogen gas (H2). Another method involves the reaction of iron oxide (FeO) with hydrochloric acid to form FeCl2 and water (H2O). FeCl2 can also be obtained by reducing iron(III) chloride (FeCl3) with hydrogen gas (H2) or with another reducing agent.
To balance the chemical equation FeCl2 + Na2CO3 → 2NaCl + FeCO3, you would need to adjust the coefficients in front of each compound. Start by balancing the metal atoms, then balance the non-metal atoms, and finally balance the charges. In this case, the balanced equation is 2FeCl2 + 3Na2CO3 → 6NaCl + FeCO3.
This reaction is a displacement reaction, where iron (Fe) displaces hydrogen (H) in hydrochloric acid (HCl) to form iron(II) chloride (FeCl2) and hydrogen gas (H2).
The reaction between iron and hydrochloric acid can be represented by the following equation: Fe + 2HCl → FeCl2 + H2. This reaction produces iron(II) chloride (FeCl2) and hydrogen gas (H2).
The reaction between FeSO4 (iron(II) sulfate) and BaCl2 (barium chloride) will produce a precipitate of barium sulfate (BaSO4) and iron(II) chloride (FeCl2) in solution. The balanced chemical equation for the reaction is: FeSO4 + BaCl2 -> BaSO4 + FeCl2.