If 705g of water is heated 889J how much will its temperature increase?

Answer 1

It take 4.2 Joules to raise 1 gram of water by 1 degree Celsius. Each gram of water is heated by 1.26 Joules, creating an increase in temperature of .3 degrees Celsius.

Answer 2

To find the temperature increase, you can use the formula: ( Q = mc\Delta T ), where ( Q ) is the heat energy transferred, ( m ) is the mass of the substance, ( c ) is the specific heat capacity of the substance, and ( \Delta T ) is the change in temperature. Rearrange the formula to solve for ( \Delta T ) by dividing both sides by ( mc ): ( \Delta T = \frac{Q}{mc} ). Substitute ( Q = 889J ), ( m = 705g = 0.705kg ), ( c = 4.18 J/g°C ), and calculate to find the change in temperature.