If there were a chain of 20K and Br atoms attached to each other, somehow, then the formula would be written as K20Br20. Since only one K+ ion attaches to one Br- ion, the formula is written as KBr, regardless of how many are there.
One formula unit of MgBr2 has three ions; one Mg2+ ion and two Br- ions. One mole of MgBr2 formula units has one mole of Mg2+ ions and two moles of Br- ions, for a total of three moles of ions.
The ions are Sn2+ and Br-, so the formula is SnBr2.
The atomic ratio Sr/Br is 2.
Br is the chemical symbol (not formula) of bromine.
KBr2 does NOT exist, bromide (being Br-) has a valency of (minus) one, so the only possibility is KBr, potassium bromide, in solution as ions: K+ and Br-
One formula unit of MgBr2 has three ions; one Mg2+ ion and two Br- ions. One mole of MgBr2 formula units has one mole of Mg2+ ions and two moles of Br- ions, for a total of three moles of ions.
The ions are Sn2+ and Br-, so the formula is SnBr2.
Ba+2 Br-1 -----> these are the ions and their chargesBa+2 Br+1 Br+1 ----> the charges must add to zero, so one positive Br ion is added to cancel out the +2 Ba ionBaBr2 ------> simplifyName: Barium bromide
Ca2+, AL3+,BR-
The atomic ratio Sr/Br is 2.
Fe+2 Br-1 = The ions and their chargesFe+2 Br-1 Br-1 = The ions have to add up to zero, so two -1 bromine ions cancel out one +2 iron ionFeBr2 = simplification and final answer
KBr2 does NOT exist, bromide (being Br-) has a valency of (minus) one, so the only possibility is KBr, potassium bromide, in solution as ions: K+ and Br-
Br is the chemical symbol (not formula) of bromine.
Cu+2 Br-1
write down the formulae of the ionic compounds which contain the following pairs of a) Ca2+ and P3---->Ca3P2 b)Fe3+ and Br---->FeBr3 c) Mg2+ AND NO-3---> Mg3NO2 D) NH4+ AND S2----> S2(NH4)
Mg+2 Br-1 ------> these are the ions with their chargesMg+2 Br-1 Br-1 -----> the charges have to add up to zero by adding one negative Br atom to cancel out the +2 positive Mg atomMgBr2 -----> simplifyName: Magnesium bromide
Ca+2 Br-1 -----> these are the ions and their chargesCa+2 Br-1 Br-1 ------> the charges have to add up to zero, so one -1 Br ion is added to cancel out the +2 Ca.CaBr2 -----> simplify