You need the k value to solve this.
To find the Ka of the first ionization of H3PO4, you need to set up an ICE table and use the formula for Ka. Given that the pH at equilibrium is 3, you can calculate the concentration of H+ ions at equilibrium. Then, use this concentration to calculate the concentration of the other species in the reaction and plug them into the Ka expression to find the Ka value.
What normally are called reactants form products. As more products are formed, in some reactions, they start undergoing the reverse reaction to reform the original reactants. The forward reaction has a certain rate(speed that it occurs) which slows asreactants are used up. The reverse reaction initially has zero rate because there are none of those substances to reverse the process but that reverse rate speeds up as more of those substances are formed. When both rates areEQUAL, the system is at chemical equilibrium.
To determine if acid or carbonate was in excess initially, you can titrate the reaction mixture with an appropriate base of known concentration. The point where the base completely neutralizes the acid will indicate the amount of acid present initially. Any excess base after this point would suggest that the initial excess was in the carbonate.
Initially, there are 4.12 L * 0.850 mol/L = 3.502 mol of H3PO4 in the solution. After dilution to 10.00 L, the new concentration is 3.502 mol / 10.00 L = 0.3502 M.
When K_a is close to the molarity of the reactants you can use successive approximtions as opposed to the quadratic formula. You simply ignore the value of x being subtracted from the reactants to find the value of x. This will give you an answer which you then plug back into the equation in place of the x value you initially ignored. If you repeat this procedure of plugging each new answer back in for x, you will find that the answer will begin to become closer and closer to the same value: This is the actual value of x. This should be the initial set up for this type of problem: K_a = some x value (ie. x^2) / (concentration - x)(concentration - x) The K_a value will be given.
Since the reaction mix initially contains no products, all of the 0.230 M of AB will react. The reaction is 2AB -> A + B, so at equilibrium, the concentrations of A and B will each be 0.115 M.
To determine the concentration of HF in an equilibrium mixture established by adding 1 mol each of H2 and F2 to a 1.00 L container, we first recognize that the reaction is (H_2 + F_2 \rightleftharpoons 2HF). Assuming the reaction goes to completion, we would initially have 1 mol of H2 and 1 mol of F2, which would produce 2 mol of HF. Since the total volume is 1.00 L, the concentration of HF at equilibrium would be 2 M. However, the actual equilibrium concentrations depend on the equilibrium constant (K) for this reaction at the given temperature, which would need to be known to provide a precise answer.
To find the Ka of the first ionization of H3PO4, you need to set up an ICE table and use the formula for Ka. Given that the pH at equilibrium is 3, you can calculate the concentration of H+ ions at equilibrium. Then, use this concentration to calculate the concentration of the other species in the reaction and plug them into the Ka expression to find the Ka value.
molecules go with the concentration gradient, depending if the cell is hypotonic or hypertonic (research that.)AnswerBecause the molecules of solute are mutually repelled but are attracted to the molecules of the solvent. They therefore tend to spread throughout the solvent until they are evenly distributed.Actual AnswerMolecules diffuse because they are always randomly moving around (brownian motion). The molecules have no real sense of high or low concentration. It's their random movement that make it seem like they go from high to low concentration.
The dye crystals will dissolve in the water over time, spreading evenly throughout the solution. This process is known as diffusion, where particles move from an area of higher concentration to lower concentration until reaching equilibrium.
Buchenwald, though initially it was called Ettersberg (for a couple of weeks or so).
Increasing substrate concentration can initially increase enzyme activity as more substrate molecules are available for the enzyme to bind to. However, at a certain point, the enzyme becomes saturated with substrate molecules and enzyme activity levels off. Very high substrate concentrations can also lead to competitive inhibition or product inhibition which can inhibit enzyme activity.
In a competitive market, when the price is initially below the equilibrium level, there will be excess demand as consumers are willing to buy more at the lower price. This increased demand will lead to upward pressure on the price, as suppliers respond to the higher demand by raising their prices. Eventually, the price will rise until it reaches the equilibrium level, where quantity supplied equals quantity demanded.
Sodium acetate is called a basic salt because a solution of it in initially pure water has a pH value well above the neutral value of 7. This occurs because acetate ions when dissolved in water must come to an equilibrium in the ionic reaction C2H3O2-1 + H2O <-> C2H4O2 + OH-1 and sodium ions when dissolved in water must come to an equilibrium in the ionic reaction Na+1 + H2O <-> NaOH + H+1. Additionally, water itself must maintain an equilibrium in the ionic reaction H2O <-> H+1 + OH-1. The values of these three equilibrium constants are such that the net result is a higher concentration of hydroxide ions than of hydrogen ions in a solution of sodium acetate. These relative concentrations of hydroxide and hydrogen ions is the defining characteristic of a basic (or alkaline) aqueous solution: Such a relative concentration of hydroxide and of hydrogen ions, although not all the other characteristics of a sodium acetate solution, could be achieved by dissolving an appropriate amount of the base sodium hydroxide in initially pure water.
equilibrium means the rate of forward reaction = rate of backward reaction... there are three types of equilibrium 1. amount of products > amount of reactants 2. amount of products = amount of reactants 3. amount of products < amount of reactants
The chocolate bar was initially made in 1925 by Hershey and was then modified in 1996 and 2008 for more peanuts and less expensive cocoa, respectively.
The rate of diffusion typically decreases over time as the concentration gradient between two areas diminishes. Initially, diffusion occurs rapidly when there is a significant difference in concentration, but as equilibrium is approached, the rate of diffusion slows down.