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If a student has a beaker containing 55 grams of water at 100 degrees Celsius how much heat is needed to convert the water to steam?
Wiki User
∙ 11y ago
The formula for any heat transfer is: q=mcT, where q=amount of heat, m=mass of the object, c=specific heat capacity of the object, and T=the change in temperature.
What the problem doesn't have is the starting temperature, so I'll assume a room temperature of 25C. Water boils at 100C, so the change in temp is 75C (100C-25C). Fortunately, 55mL of water has a mass of 55g, and the specific heat capacity of water is 1 calorie per gram per degree celsius (1 cal/g-C).
Plug in our numbers: q=(55g)(1 cal/g-C)(75C) = 4125 cal, or 4.1x103cal to observe significant numbers.
If you need the answer in another measure of energy, such as joules, the conversion is 4.184J=1 cal. And our answer would be (4.1x103cal)(4.184J/cal) = 1.7x104J.
Wiki User
∙ 14y ago
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