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If gas has a volume of 600 ml at 27'c if it is cooled to a temperature of 23'c what will its volume be?
Wiki User
∙ 14y ago
You can use the Ideal Gas Law here: PV=nRT. First you need to find the pressure in the first situation, where V1=600 ml and T1=300 K (temperature is measured in absolute, meaning kelvins, rather than celsius).
P=nRT1/V1
Then, you're looking for the volume in the second situation, so rearrange the Gas Law here:
V2=nRT2/P
Substitute P=nRT1/V1 into this equation to get:
V2=(nRT2V1)/(nRT1)
After some simplification, we reach:
V2=T2V1/T1
And substituting the numerical values gives you:
V2=(293 K)(.600 L)/(300 K)=.586 L=586 L
Wiki User
∙ 14y ago
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