There are a total of three structural isomers of C7H16 that have no secondary hydrogen atoms. These isomers are 2-methylhexane, 3-methylhexane, and 2,2-dimethylpentane.
/\/\/\
The correct molecular formula for C7H16 is heptane, which is a straight-chain alkane hydrocarbon with seven carbon atoms and sixteen hydrogen atoms.
The C7H16 isomer with the highest boiling point is heptane. This is because heptane has a linear structure with stronger London dispersion forces compared to its branched isomers, resulting in higher boiling points due to increased surface contact between molecules.
This formula corresponds to several saturated isomers of heptane as 2-methylhexane, 3-methylhexane, 2,3-dimethyl pentane e.t.c.
The structural formula of 2-ethyl hexane is CH3(CH2)3CH(CH3)CH2CH3. It consists of an ethyl group (C2H5) attached to the second carbon atom of a hexane chain.
There are nine isomers of C7H16. These include seven structural isomers (heptane, 2-methylhexane, 3-methylhexane, 2,2-dimethylpentane, 2,3-dimethylpentane, 3,3-dimethylpentane, and 2,2,3-trimethylbutane) and two positional isomers (methylhexane and dimethylpentane).
There are 16 hydrogen atoms in 1 mole of C7H16.
/\/\/\
The correct molecular formula for C7H16 is heptane, which is a straight-chain alkane hydrocarbon with seven carbon atoms and sixteen hydrogen atoms.
Answer ...There are 5 structural isomers of C6H14. The structural names are: hexane, 2-methylpentane, 3-methylpentane, , 2,3-dimethylbutane and 2,2-dimethylbutane.
/\/\/\
The C7H16 isomer with the highest boiling point is heptane. This is because heptane has a linear structure with stronger London dispersion forces compared to its branched isomers, resulting in higher boiling points due to increased surface contact between molecules.
the answer is D.
Yes, 2,3-dimethylpentane has the empirical formula C7H16.
- Cyclobutane: four carbons single-bonded in a square pattern, each with two hydrogens. H2C----CH2 | | H2C----CH2 - 1-butene: four carbons in a chain with a double bond between the first and second carbons: H2C==CH--CH2--CH3 - 2-butene: four carbons in a chain with a double bond between the second and third carbons: H3C--CH==CH--CH3
How could it be? Where is the oxygen count? C7H16 + 11O2 -> 7CO2 + 8H2O
C7h16