You get a dilute solution.
With 4 litres of water, you have more solvent (H2O) than solvent (HCl) than you originally had.
There are 30 liters of hydrochloric acid in 300 liters of a solution that is 10% hydrochloric acid by volume.
To find the number of moles of solute in the solution, you first need to calculate the amount of solute in moles using the formula: moles = molarity x volume (in liters). Since the volume given is in milliliters, you need to convert it to liters by dividing by 1000. Then, you can calculate the moles of hydrochloric acid in 30 ml of 0.2M solution.
To determine the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters). Molarity is calculated by dividing the moles of solute by the volume of the solution in liters. The formula for molarity is M moles of solute / liters of solution.
The scientist poured 0.00348 liters of hydrochloric acid into the beaker.
To find the concentration of the hydrochloric acid solution, you first need to convert the mass of the precipitate to moles using the molar mass of silver chloride. Then, use the mole ratio from the balanced chemical equation to find the moles of hydrochloric acid used. Finally, calculate the molarity by dividing the moles of hydrochloric acid by the volume in liters.
There are 30 liters of hydrochloric acid in 300 liters of a solution that is 10% hydrochloric acid by volume.
A 2M solution of hydrochloric acid would contain 2 moles of hydrochloric acid per liter of solution. To determine the amount of hydrochloric acid in a certain volume of 2M solution, you can use the formula: moles = Molarity x Volume (in liters).
0.0532
To find the number of moles of solute in the solution, you first need to calculate the amount of solute in moles using the formula: moles = molarity x volume (in liters). Since the volume given is in milliliters, you need to convert it to liters by dividing by 1000. Then, you can calculate the moles of hydrochloric acid in 30 ml of 0.2M solution.
7 liters of a 20% acid solution consists of 1.4 liters of acid (20% of the total volume) mixed with 5.6 liters of water (80% of the total volume). The amount of acid isn't going to change in the new solution. You are just going to add enough water to make it a 10% solution instead of a 20% solution. So it will be more dilute. That means that 1.4 liters of acid will represent 1/10 of the volume of the new solution. So the total volume of the new solution will be 10 x 1.4 or 14 liters. The amount of water in the new solution will be 14 - 1.4 = 12.6 liters. That is a difference of 12.6 - 5.6 = 7 liters from the amount of water you started with. So you need to add 7 liters of water to the original 20% solution to make it a 10% solution. This makes sense because if you double the amount of the mixture from 7 liters to 14 liters and the amount of acid is unchanged, the solution will be half as strong.
0.0932 L
To determine the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters). Molarity is calculated by dividing the moles of solute by the volume of the solution in liters. The formula for molarity is M moles of solute / liters of solution.
The scientist poured 0.00348 liters of hydrochloric acid into the beaker.
0.0932 L
0.0932 L
0.0532 L
To find the concentration of the hydrochloric acid solution, you first need to convert the mass of the precipitate to moles using the molar mass of silver chloride. Then, use the mole ratio from the balanced chemical equation to find the moles of hydrochloric acid used. Finally, calculate the molarity by dividing the moles of hydrochloric acid by the volume in liters.