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12 days represents four half-lives in this case. Therefore you would have a half of a half of a half of a half of 16 g, or 1/16 * 16 g, or 1 g.

You'd also have 15 g of something else. The object doesn't actually disappear, it just changes into a different substance.

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12y ago
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12y ago

If the half-life is 3 days, then 18 days is 6 half-lives. 2-6 is 0.015625, so (48) (0.015625) or 0.75 g would remain.

The equation for half-life is

AT = A0 2 (-T/H)

where A0 is the starting activity, AT is the activity at some time T, and H is half-life in units of T.

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15y ago

1 g

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Q: If you have 16 g of a substance that has a half-life of 3 days after 12 days you will have how much of the substance remaining?
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