There is quite a bit of missing information here.
a. Lets assume your pressure is 1 atm.
b. Lets also assume you are distilling methanol and water.
c. Lets assume your theoretical plate efficiency is 100%
d. Lets ALSO assume your initial concentration is 0.1 mol% methanol.
Given these condition it takes about 1.25 theoretical plates to distill it to about 49 mol%.
The number of plates depends heavily on the initial concentration.
Working backwards from 49mol%, exactly one stage would place you at an initial concentration of about 8%. Exactly two would place you at about 1 mol%.
See also the McCabe Thiele method: http://en.wikipedia.org/wiki/McCabe-Thiele_method
Percent yield = Actual Yield / Theoretical Yield * 100 hope that helps :)
94% Ethanol 5% methanol 1% other
because of variable in the situation '
Dissolve 30 g KOH in 100 mL methanol.
Not at all. Just be consistent with the units of both actual and theoretical yield.
13.6% methanol solution.
50% methanol will damage the membrane more than 25% acetone. we did the lab.
Percent error = (actual value - theoretical value) / theoretical value * 100%
With 25ml methanol and 75ml water, there is 100ml in total. So there is 25/100 = 25% by volume methanol.
Percent Error = {Absolute value (Experimental value - Theoretical Value) / Theoretical Value }*100
8 percent
The sodium methoxide reacts with the water to produce sodium hydroxide an methanol.
Yes, methanol does kill bacteria, especially if it is 70 percent or more, this allows penetration of the cell wall of the organism.
by using fractional distillation
25%
Percent yield = Actual Yield / Theoretical Yield * 100 hope that helps :)
Possibly, by low pressure distillation, but it is not easy.