3
Two "R" alkyl groups are attached to carbinol carbon in secondary alcohlos
Simple answer ... you need at least one hydrogen attached to carbinol carbon. in other words, you have a hydrogen on the oxygen to give you the hydroxyl group that is attached to the carbinol carbon, but you also need a hydrogen coming off that carbon. The reason - your reagent, such as chromic acid, joins with the alcohol at the position of the hydroxyl group, which leads to an H2O molecule being shot off. The chromic acid provides the -OH of that water, but takes the H off the hydroxyl group to get the 2nd hydrogen atom. You would now have a chromate ester + water. The water then takes off a hydrogen atom attached to the carbinol carbon, which leaves the electrons to form a double bond with the Oxygen atom. Without the hydrogen attached to the carbinol carbon ... like in a tertiary alcohol ... oxidation could only take place by breaking carbon-carbon bonds, which requires severe conditions. Even if this did happen, you would get a mixture of products.
Methanol is a primary alcohol. You can't have a secondary alcohol until you get to propanol, where 1-propanol is a primary alcohol and 2-propanol is a secondary alcohol (also called sec-propyl alchohol or isopropanol). Secondary alcohols are alcohols where the -OH group is attached to a carbon that has two carbon groups attached to it. The first tertiary alcohol is t-butyl alcohol, otherwise known as 2-methyl-2-propanol. In that molecule the -OH group is attached to a carbon that has three carbon groups attached to it.
Both aldehydes and ketones contain a C=O (carbon double bond oxygen). Ketones have this C=O somewhere in their carbon chain, but not at the start or end of the chain (ie: there are more carbons attached to the carbon containing the double bond oxygen, and no hydrogens bonded to that carbon). Aldehydes have there C=O at the end, or start of the chain, and to maintain the octet rule, there is hydrogen bonded to the oxygen containing carbon (please note that it is a C=O). The functional group of alcohol is OH. This OH is bonded directly to the last (or first) carbon in the chain. The big difference is that the carbon bond oxygen is a single bond and the hydrogen is bonded to the oxygen (not the carbon, as the case of aldehydes).
In a primary (1°) alcohol, only attached to one alkyl group; In a secondary (2°) alcohol, attached two alkyl groups & tertiary (3°) alcohol, attached three alkyl groups Actually, that person has you more confused. This is an easy way to remember what is 1 degree, 2 degree or 3 degree of Alcohols. 1 degree: R-- CH2 -- OH 2 degree: R2 -- CH -- OH 3 degree: R3 -- C -- OH R = CH3
Tertiary
Yes but you have to draw it as a 3 carbon ring structure (like a triangle) and the 1st carbon would have a CH3 and an OH.
Tertiary alcohols are also bonded to three other carbon atoms (whereas secondary alcohols are bonded to two, primary alcohols to one). These other carbon atoms share their electronegative charges with the middle carbon.
Two "R" alkyl groups are attached to carbinol carbon in secondary alcohlos
yes it is a tertiary because it is off a 3rd carbon from the main strand of Carbon chain.Type your answer here...
A secondary carbon is a carbon atom that is singly bonded to two other carbon atoms.
Just check for how many carbon groups are attached to the carbon group that OH is on. Since OH can only bond to one carbon, you see how many other carbons are attached to that one. The maximum is 3, since carbon usually only has 4 bonds total, making it tertiary structure. Likewise, 2 carbon groups attached to that carbon makes it secondary, and one C group is primary. Just write out a diagram and it should be easy!
Simple answer ... you need at least one hydrogen attached to carbinol carbon. in other words, you have a hydrogen on the oxygen to give you the hydroxyl group that is attached to the carbinol carbon, but you also need a hydrogen coming off that carbon. The reason - your reagent, such as chromic acid, joins with the alcohol at the position of the hydroxyl group, which leads to an H2O molecule being shot off. The chromic acid provides the -OH of that water, but takes the H off the hydroxyl group to get the 2nd hydrogen atom. You would now have a chromate ester + water. The water then takes off a hydrogen atom attached to the carbinol carbon, which leaves the electrons to form a double bond with the Oxygen atom. Without the hydrogen attached to the carbinol carbon ... like in a tertiary alcohol ... oxidation could only take place by breaking carbon-carbon bonds, which requires severe conditions. Even if this did happen, you would get a mixture of products.
Methanol is a primary alcohol. You can't have a secondary alcohol until you get to propanol, where 1-propanol is a primary alcohol and 2-propanol is a secondary alcohol (also called sec-propyl alchohol or isopropanol). Secondary alcohols are alcohols where the -OH group is attached to a carbon that has two carbon groups attached to it. The first tertiary alcohol is t-butyl alcohol, otherwise known as 2-methyl-2-propanol. In that molecule the -OH group is attached to a carbon that has three carbon groups attached to it.
A secondary alcohol undergoes oxidation to yield a ketone; a primary alcohol forms an aldehyde instead, and a tertiary alcohol usually does not form either a ketone or an alcohol, because the carbon having the OH group in a tertiary alcohol already has three bonds to other carbon atoms and therefore cannot form a double bond to oxygen without more extensive breaking of other bonds in the tertiary alcohol.
Both aldehydes and ketones contain a C=O (carbon double bond oxygen). Ketones have this C=O somewhere in their carbon chain, but not at the start or end of the chain (ie: there are more carbons attached to the carbon containing the double bond oxygen, and no hydrogens bonded to that carbon). Aldehydes have there C=O at the end, or start of the chain, and to maintain the octet rule, there is hydrogen bonded to the oxygen containing carbon (please note that it is a C=O). The functional group of alcohol is OH. This OH is bonded directly to the last (or first) carbon in the chain. The big difference is that the carbon bond oxygen is a single bond and the hydrogen is bonded to the oxygen (not the carbon, as the case of aldehydes).
primary - if only one carbon is attached to the carbon attached to the oxygen for example CH3-CH2-OH Secondary - if two carbons are attached to the carbon attached to the oxygen for example ...............................CH3-CH-OH .........................................| .......................................CH3 Tertiary - if three carbons are attached to the carbon attached to the oxygen for example ................................CH3 ..................................| ..........................CH3-C-OH ..................................| ................................CH3 (ignore the .'s it was the only way I could make the diagrams)