In an exactly.200M solution of benzoic acid a monoprotic acid the H plus 3.55 and times 10 and ndash3M. What is the Ka for benzoic acid 6.3 and times 10 and ndash5 1.77 and times 10 and ndash2 8.88 an?

Answer 1

The correct Ka value for benzoic acid is 6.3 x 10^-5. This can be calculated using the equation Ka = [H+][C6H5COO-] / [C6H5COOH]. Plugging in the values given ([H+] = 3.55 x 10^-3 M, [C6H5COOH] = 0.200 M) gives Ka = (3.55 x 10^-3)(3.55 x 10^-3) / (0.200) = 6.3 x 10^-5.