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Boron is sp2 hybridised with an empty p orbital. Both chlorine and iodine have lone electron pairs of suitable symmetry to form a partial pi bond with the empty orbital of boron. This partial pi bond effect is stronger and more significant in BCl3 because there is a better energy match between the empty p of boron (LUMO) and the lone pairs of Cl (HOMO) than between boron p and the lone pairs of iodine. As a Lewis acid, boron takes an electron pair into its empty p orbital. In BCl3, the significant pi bond means that this p orbital is less electron deficient and therefore hinders the ability of the p orbital to accept an electron pair, so it is a weaker acid than BI3. Maybe consult a textbook or website for a picture to help you visualise Boron in sp2 hybridised state.

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Q: In boron haildes why BCl3 is weakest Lewis acid but BI3 is a strongest Lewis acid?
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Related questions

Lewis dot structure of boron?

the Lewis structure of B or Boron would have three small dots posing as electrons. These dots can be placed anywhere around the B symbol.


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