Your reaction is AgNO3 + Na ==> NaNO3 + AgIn this reaction Ag goes from 1+ to zero, so it has been reduced. Na goes from zero to 1+ so it has been oxidized.
In the redox reaction AgNO3 + NaNO3 + Ag, silver (Ag) is reduced from Ag+ to Ag with the gain of one electron. Therefore, one electron is transferred in this reaction.
In the redox reaction, silver (Ag) has been reduced because it gains electrons in forming solid silver (Ag) from silver nitrate (AgNO3).
In the reaction ( 2Ag^{+} + 2e^{-} \rightarrow 2Ag ), two electrons are transferred per silver ion, so a total of four electrons are transferred in the overall reaction.
In this reaction, silver (Ag) has been oxidized. This is because silver changes from an oxidation state of 0 in Ag metal to an oxidation state of +1 in AgNO3. Oxidation involves the loss of electrons.
They will form NaNO3 in aqueous solution, and AgOH would precipitate out of solution. AgNO3(aq) + NaOH(aq) --> AgOH(s) + NaNO3(aq) This is an example of a double displacement/replacement reaction.
Silver (Ag)
In the redox reaction AgNO3 + NaNO3 + Ag, silver (Ag) is reduced from Ag+ to Ag with the gain of one electron. Therefore, one electron is transferred in this reaction.
Sodium (Na) has been reduced.
In the redox reaction, silver (Ag) has been reduced because it gains electrons in forming solid silver (Ag) from silver nitrate (AgNO3).
In the redox reaction between silver nitrate (AgNO3) and sodium (Na) to produce sodium nitrate (NaNO3) and silver (Ag), sodium is oxidized from 0 to +1 oxidation state, losing one electron, while silver is reduced from +1 to 0 oxidation state, gaining one electron. Therefore, a total of one electron is transferred in this reaction.
If you mean a reaction of AgNO3 + Na(s) ==> NaNO3 + Ag(s), there would be ONE electron transferred.Ag^+ + 1e- ==> Ag(s) Reduction reaction Na(s) ==> Na^+ + 1e- Oxidation reaction
I cannot answer this question.
In the reaction ( 2Ag^{+} + 2e^{-} \rightarrow 2Ag ), two electrons are transferred per silver ion, so a total of four electrons are transferred in the overall reaction.
In the given redox reaction, silver nitrate (AgNO3) reacts with sodium nitrate (NaNO3) and elemental silver (Ag). The element that has been reduced is silver (Ag) because it is being converted from its ionic form (Ag^+) in AgNO3 to its elemental form (Ag). Reduction involves the gain of electrons, and in this case, Ag^+ gains an electron to become neutral Ag.
In this reaction, silver (Ag) has been oxidized. This is because silver changes from an oxidation state of 0 in Ag metal to an oxidation state of +1 in AgNO3. Oxidation involves the loss of electrons.
They will form NaNO3 in aqueous solution, and AgOH would precipitate out of solution. AgNO3(aq) + NaOH(aq) --> AgOH(s) + NaNO3(aq) This is an example of a double displacement/replacement reaction.
The reaction is: AgNO3 + NaCl = AgCl + NaNO3 Silver chloride is a white precipitate.