2NaCl + H2SO4 ---> 2HCl + Na2SO4
Na(OH)2 + H2SO4 = NaSO4 +2 H20
NaSO4
2NH3(g) + 3Mg(s) —> 3H2(g) + Mg3N2(s)
Weight of NaCl used (250g)/Total molecular weight x Avagadro's number = total molecules of NaCl.
An equation is balanced if each atom on one side of the arrow has the exact same amount on the other side. You can balance the equation by adding coefficents in front of the element, but make sure there are the same amount. For example: if you have 3 atoms of Al on the left of the arrow, and 6 atoms of Al on the right side, all you have to do is add the number 2 as a coefficient in front of the first Al to make 6 atoms of Aluminum on each side.
Na(OH)2 + H2SO4 = NaSO4 +2 H20
koh + h2so4-khso4 +h2o
NaSO4
It is NaCO3+H2SO4 ---> NASO4+H2O+CO2
2NH3(g) + 3Mg(s) —> 3H2(g) + Mg3N2(s)
Weight of NaCl used (250g)/Total molecular weight x Avagadro's number = total molecules of NaCl.
Naso4
Yes,there will be a reaction see the equation below: Zn+NaSo4= ZnSo4+Na
NaSO4
An equation is balanced if each atom on one side of the arrow has the exact same amount on the other side. You can balance the equation by adding coefficents in front of the element, but make sure there are the same amount. For example: if you have 3 atoms of Al on the left of the arrow, and 6 atoms of Al on the right side, all you have to do is add the number 2 as a coefficient in front of the first Al to make 6 atoms of Aluminum on each side.
NaSO4, if it could exist, would have a mass of 119.046 AMU. However, it cannot exist because the valencies do not agree.
This reaction could be written as 2AlBr3 = 6NaBr + Al2( CO3)3 The reaction in water would be interesting as AlBr3 hydrolyses to give a mixture of Al-OH-Br species Alumium hydroxybromide and hydrobromic acid, HBr. ALuminium carbonate is unstable and decomposes Al2(CO3)3 + 3 H2O → 2 Al(OH)3 + 3 CO2 Just because you can write a nice balanced (stoichiometric) equation it doesn't mean that is what ould actually happen!