No, these are totally different concentrations! The ratio of difference is a multiplication factor of 12.5 smaller or bigger respectively.
So: 8mM = 8 millimolar = 0.008 molar = 0.008M
and 0.1M = 0.1 molar = 100 millimolar = 100mM
To prepare 1 mM NaOH solution, you would dissolve 0.040 g of NaOH in enough water to make 1 liter of solution. This concentration is equivalent to 1 millimole of NaOH per liter of solution. Be cautious when handling NaOH as it is a caustic substance.
To calculate the concentration of a 0.1 N NaOH solution, you need to know the molar mass of NaOH which is approximately 40 g/mol. Since 1 N solution is equivalent to 1 gram equivalent weight of the solute dissolved in 1 liter of the solution, a 0.1 N NaOH solution would contain 4 g of NaOH per liter of solution.
Datagiven Mass =60 gramFormula mass=40Volume=50Molality=?m =Mass of solution_________________*LitreFormula mass Volume60 * 100040 50060000_____20000m=3gram Ans
To calculate the grams of NaOH, first find the molar mass of NaOH (22.99 g/mol for Na + 16.00 g/mol for O + 1.01 g/mol for H) = 40.00 g/mol. 9.03 x 10^23 molecules of NaOH is equivalent to 1 mole of NaOH. Therefore, 9.03 x 10^23 molecules of NaOH is equal to 40.00 grams.
KHC8H4O4(aq) + NaOH(aq) --> KNaC8H4O4(aq) + H2O(l). The molar mass of KHP is approximately 204.22 g/mol. 1.54g of KHP is equivalent to 0.00754 mol of KHP. 1 mole of NaOH reacts per mole of KHP, so .00754 mol of NaOH are needed.
.01m = 1cm
To prepare 1 mM NaOH solution, you would dissolve 0.040 g of NaOH in enough water to make 1 liter of solution. This concentration is equivalent to 1 millimole of NaOH per liter of solution. Be cautious when handling NaOH as it is a caustic substance.
To calculate the concentration of a 0.1 N NaOH solution, you need to know the molar mass of NaOH which is approximately 40 g/mol. Since 1 N solution is equivalent to 1 gram equivalent weight of the solute dissolved in 1 liter of the solution, a 0.1 N NaOH solution would contain 4 g of NaOH per liter of solution.
6
1 cm is .01m so 600cm*.01m = 6m =] -ray
NaOH and H2O form a solution of Na+(aq) and OH-(aq) ions (the solvent water, aq, is written as subscripted (aq) ) To make 1 Normal solution you need to know the equivalent of NaOH, which is calculated by dividing Molecular weight by 1, that is 40 divided by 1= 40. So the equivalent weight of NaOH is 40. To make 1 N solution, dissolve 40.00 g of sodium hydroxide in water to make volume of 1 liter.
Datagiven Mass =60 gramFormula mass=40Volume=50Molality=?m =Mass of solution_________________*LitreFormula mass Volume60 * 100040 50060000_____20000m=3gram Ans
To calculate the grams of NaOH, first find the molar mass of NaOH (22.99 g/mol for Na + 16.00 g/mol for O + 1.01 g/mol for H) = 40.00 g/mol. 9.03 x 10^23 molecules of NaOH is equivalent to 1 mole of NaOH. Therefore, 9.03 x 10^23 molecules of NaOH is equal to 40.00 grams.
KHC8H4O4(aq) + NaOH(aq) --> KNaC8H4O4(aq) + H2O(l). The molar mass of KHP is approximately 204.22 g/mol. 1.54g of KHP is equivalent to 0.00754 mol of KHP. 1 mole of NaOH reacts per mole of KHP, so .00754 mol of NaOH are needed.
To prepare a 0.1M sodium borate buffer at pH 8.5, you would first dissolve sodium borate (Na2B4O7) in water to achieve a 0.1M concentration, adjusting the pH to 8.5 using a strong base like NaOH. Keep in mind the pKa value of boric acid (the conjugate acid of borate) is around 9.2, so the buffer capacity may not be optimal at pH 8.5.
i have Audi 01N and use it
8mm tapes can only be viewed with the aid of an 8mm player. One's best bet to watch 8mm tapes in this case is to purchase another 8mm player that is not broken.