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How many ml of 0.117 M AgNO3 would be required to react exactly with the NaCl solution?
To determine this, you need the concentration of the NaCl solution. Once you have that, you can use the stoichiometry of the reaction between AgNO3 and NaCl to calculate the volume of 0.117 M AgNO3 needed. The balanced chemical equation for this reaction is: AgNO3 + NaCl → AgCl + NaNO3.
How many mL of .117M AgNO3 solution would be required to react exactly with 3.82 moles of NaCl?
Balanced equation first! AgNO3 + NaCl -> AgCl + NaNO3 all one to one, get moles AgNO3 3.82 moles NaCl (1 mole AgNO3/1 mole NaCl) = 3.82 moles AgNO3 ------------------------------- Molarity = moles of solute/Liters of solution 0.117 M AgNO3 = 3.82 moles AgNO3/Liters Liters = 3.82/0.117 = 32.6 Liters which is 32600 milliliters which is unreasonable; check answer if you can
What is total ionic for NaCl plus AgNO3?
The total ionic equation for NaCl + AgNO3 is: Na⁺ + Cl⁻ + Ag⁺ + NO₃⁻ → AgCl + Na⁺ + NO₃⁻
What will happen when 2 drops of the NaCl solution is mixed with 2 drops of the AgNO3 solution?
A white precipitate of AgCl will form as a result of the reaction between sodium chloride (NaCl) and silver nitrate (AgNO3). The reaction can be represented by the equation: NaCl + AgNO3 → AgCl + NaNO3.
What does AgNO3 and NaCl gives?
When silver nitrate (AgNO3) is mixed with sodium chloride (NaCl), a white precipitate of silver chloride (AgCl) is formed. This reaction is a double displacement reaction where the silver cation from AgNO3 and the chloride anion from NaCl switch partners to form the insoluble AgCl precipitate.
What products are formed from AgNO3 and NaCl?
AgNO3(aq) + NaCl(aq) --> AgCl(s) + NaNO3(aq)
What is the reaction for AgNO3 and NaCl?
The reaction is: NaCl + AgNO3 = NaNO3 + AgCl Silver chloride is a white precipitate.
What does the sign plus in a chemical equation?
1. That a reactant is added: NaCl + AgNO3 = NaNO3 + AgCl 2. It is also in the symbols of cations: Na+, Fe2+, Al3+ etc.
How many ml of 0.117 M AgNO3 would be required to react exactly with the NaCl solution?
To determine this, you need the concentration of the NaCl solution. Once you have that, you can use the stoichiometry of the reaction between AgNO3 and NaCl to calculate the volume of 0.117 M AgNO3 needed. The balanced chemical equation for this reaction is: AgNO3 + NaCl → AgCl + NaNO3.
How many mL of .117M AgNO3 solution would be required to react exactly with 3.82 moles of NaCl?
Balanced equation first! AgNO3 + NaCl -> AgCl + NaNO3 all one to one, get moles AgNO3 3.82 moles NaCl (1 mole AgNO3/1 mole NaCl) = 3.82 moles AgNO3 ------------------------------- Molarity = moles of solute/Liters of solution 0.117 M AgNO3 = 3.82 moles AgNO3/Liters Liters = 3.82/0.117 = 32.6 Liters which is 32600 milliliters which is unreasonable; check answer if you can
Why is AgNo3 and NaCl least desirable?
These compounds react forming a white insoluble precipitate - silver chloride: NaCl + AgNO3 = AgCl + NaNO3
What is total ionic for NaCl plus AgNO3?
The total ionic equation for NaCl + AgNO3 is: Na⁺ + Cl⁻ + Ag⁺ + NO₃⁻ → AgCl + Na⁺ + NO₃⁻
What will happen when 2 drops of the NaCl solution is mixed with 2 drops of the AgNO3 solution?
A white precipitate of AgCl will form as a result of the reaction between sodium chloride (NaCl) and silver nitrate (AgNO3). The reaction can be represented by the equation: NaCl + AgNO3 → AgCl + NaNO3.
What is the correction for AgNo3 plus NaCl yields NaCl plus Ag No3?
The reaction is: AgNO3 + NaCl = AgCl + NaNO3 Silver chloride is a white precipitate.
Is mixiing NaCl with AgNO3 achemical or physical change?
chemical
What does AgNO3 and NaCl gives?
When silver nitrate (AgNO3) is mixed with sodium chloride (NaCl), a white precipitate of silver chloride (AgCl) is formed. This reaction is a double displacement reaction where the silver cation from AgNO3 and the chloride anion from NaCl switch partners to form the insoluble AgCl precipitate.
What is the Balanced equation for AgNO3 plus NaCL?
Cu + AgNO3 --> Ag + Cu(NO3)2See formation of silver crystalshttp://www.youtube.com/watch?v=rgYhkVy5cBU
