This depends on the amounts of these reactants.
To determine this, you need the concentration of the NaCl solution. Once you have that, you can use the stoichiometry of the reaction between AgNO3 and NaCl to calculate the volume of 0.117 M AgNO3 needed. The balanced chemical equation for this reaction is: AgNO3 + NaCl → AgCl + NaNO3.
Balanced equation first! AgNO3 + NaCl -> AgCl + NaNO3 all one to one, get moles AgNO3 3.82 moles NaCl (1 mole AgNO3/1 mole NaCl) = 3.82 moles AgNO3 ------------------------------- Molarity = moles of solute/Liters of solution 0.117 M AgNO3 = 3.82 moles AgNO3/Liters Liters = 3.82/0.117 = 32.6 Liters which is 32600 milliliters which is unreasonable; check answer if you can
The total ionic equation for NaCl + AgNO3 is: Na⁺ + Cl⁻ + Ag⁺ + NO₃⁻ → AgCl + Na⁺ + NO₃⁻
A white precipitate of AgCl will form as a result of the reaction between sodium chloride (NaCl) and silver nitrate (AgNO3). The reaction can be represented by the equation: NaCl + AgNO3 → AgCl + NaNO3.
When silver nitrate (AgNO3) is mixed with sodium chloride (NaCl), a white precipitate of silver chloride (AgCl) is formed. This reaction is a double displacement reaction where the silver cation from AgNO3 and the chloride anion from NaCl switch partners to form the insoluble AgCl precipitate.
AgNO3(aq) + NaCl(aq) --> AgCl(s) + NaNO3(aq)
The reaction is: NaCl + AgNO3 = NaNO3 + AgCl Silver chloride is a white precipitate.
1. That a reactant is added: NaCl + AgNO3 = NaNO3 + AgCl 2. It is also in the symbols of cations: Na+, Fe2+, Al3+ etc.
To determine this, you need the concentration of the NaCl solution. Once you have that, you can use the stoichiometry of the reaction between AgNO3 and NaCl to calculate the volume of 0.117 M AgNO3 needed. The balanced chemical equation for this reaction is: AgNO3 + NaCl → AgCl + NaNO3.
Balanced equation first! AgNO3 + NaCl -> AgCl + NaNO3 all one to one, get moles AgNO3 3.82 moles NaCl (1 mole AgNO3/1 mole NaCl) = 3.82 moles AgNO3 ------------------------------- Molarity = moles of solute/Liters of solution 0.117 M AgNO3 = 3.82 moles AgNO3/Liters Liters = 3.82/0.117 = 32.6 Liters which is 32600 milliliters which is unreasonable; check answer if you can
These compounds react forming a white insoluble precipitate - silver chloride: NaCl + AgNO3 = AgCl + NaNO3
The total ionic equation for NaCl + AgNO3 is: Na⁺ + Cl⁻ + Ag⁺ + NO₃⁻ → AgCl + Na⁺ + NO₃⁻
A white precipitate of AgCl will form as a result of the reaction between sodium chloride (NaCl) and silver nitrate (AgNO3). The reaction can be represented by the equation: NaCl + AgNO3 → AgCl + NaNO3.
The reaction is: AgNO3 + NaCl = AgCl + NaNO3 Silver chloride is a white precipitate.
chemical
When silver nitrate (AgNO3) is mixed with sodium chloride (NaCl), a white precipitate of silver chloride (AgCl) is formed. This reaction is a double displacement reaction where the silver cation from AgNO3 and the chloride anion from NaCl switch partners to form the insoluble AgCl precipitate.
Cu + AgNO3 --> Ag + Cu(NO3)2See formation of silver crystalshttp://www.youtube.com/watch?v=rgYhkVy5cBU