No. Acetic acid (CH3COOH) is a weak acid, however, sodium acetate (CH3COONa) is a salt or ionic compound formed in a neutralisation reaction (proton transfer reaction, or simply put: reaction between an acid and a base). For example: CH3COOH (aq) + NaOH (aq) --> CH3COONa (aq) + H2O (l)
Since the sodium acetate is in aqueous solution (dissolved in water), it will actually have a pH that is slightly basic (ie: less than 7). This is due to the pH of salt solutions of some salts being other than neutral (pH of 7) but that is another question entirely.
Hope that this helps.
CH3COOH + NaOH = CH3COONa + H2O
CH3COOH+NaOH=CH3COONa+H2O
CH3COONa + NaOH ------------->(in presence of CaO) CH4 + Na2CO3
the products are CH3COOH + NaOH ------CH3COONa + H2O
CH3COOH + NaHCO3 ---> CH3COONa + H2O + CO2
CH3COOH + NaOH = CH3COONa + H2O
CH3COOH+NaOH=CH3COONa+H2O
CH3COONa + NaOH ------------->(in presence of CaO) CH4 + Na2CO3
the products are CH3COOH + NaOH ------CH3COONa + H2O
CH3COOH + NaHCO3 ---> CH3COONa + H2O + CO2
CH3COOC6H4COOH+NaOH------>CH3COONa+C6H5(OH)COONa
CH3COOH + NaHCO3 --> CH3COONa + H2O + CO2
ITS: CH3COONa --> CH3COO- + Na+ Or if its CH3COONa . 3H2O --> CH3COONa + 3H2O
CH3COOH + NaOH -----> CH3COONa + H2O(Ethanoic acid) (Sodium hydroxide) (Sodium Acetate) (Water)
Glacial acetic acid reacts with sodium hydroxide to give sodium acetate and water CH3COOH + NaOH = CH3COONa + H2O
ch3coona+FECL2
You will get sodium ethanoate, carbon dioxide and water NaHCO3 + CH3COOH -> CH3COONa + CO2 + H2O