No. Acetic acid (CH3COOH) is a weak acid, however, sodium acetate (CH3COONa) is a salt or ionic compound formed in a neutralisation reaction (proton transfer reaction, or simply put: reaction between an acid and a base). For example: CH3COOH (aq) + NaOH (aq) --> CH3COONa (aq) + H2O (l)
Since the sodium acetate is in aqueous solution (dissolved in water), it will actually have a pH that is slightly basic (ie: less than 7). This is due to the pH of salt solutions of some salts being other than neutral (pH of 7) but that is another question entirely.
Hope that this helps.
The reaction between aqueous acetic acid (CH3COOH) and aqueous sodium hydroxide (NaOH) forms water (H2O) and sodium acetate (CH3COONa). The balanced chemical equation is: CH3COOH + NaOH -> H2O + CH3COONa
When CH3COONa reacts with HCl, it forms acetic acid (CH3COOH) and sodium chloride (NaCl). This reaction is a neutralization reaction where the sodium acetate reacts with the hydrochloric acid to produce acetic acid and sodium chloride.
the products are CH3COOH + NaOH ------CH3COONa + H2O
The reaction between sodium hydroxide (NaOH) and acetic acid (CH3COOH) forms sodium acetate (CH3COONa) and water (H2O). The balanced chemical equation is: CH3COOH + NaOH -> CH3COONa + H2O.
The balanced equation for the reaction between acetic acid (CH3COOH) and sodium hydrogen carbonate (NaHCO3) is: CH3COOH + NaHCO3 -> CH3COONa + H2O + CO2 This reaction produces sodium acetate (CH3COONa), water (H2O), and carbon dioxide (CO2).
The reaction between aqueous acetic acid (CH3COOH) and aqueous sodium hydroxide (NaOH) forms water (H2O) and sodium acetate (CH3COONa). The balanced chemical equation is: CH3COOH + NaOH -> H2O + CH3COONa
CH3COOH + NaOH -----> CH3COONa + H2O(Ethanoic acid) (Sodium hydroxide) (Sodium Acetate) (Water)
When CH3COONa reacts with HCl, it forms acetic acid (CH3COOH) and sodium chloride (NaCl). This reaction is a neutralization reaction where the sodium acetate reacts with the hydrochloric acid to produce acetic acid and sodium chloride.
the products are CH3COOH + NaOH ------CH3COONa + H2O
The reaction between sodium hydroxide (NaOH) and acetic acid (CH3COOH) forms sodium acetate (CH3COONa) and water (H2O). The balanced chemical equation is: CH3COOH + NaOH -> CH3COONa + H2O.
The balanced equation for the reaction between acetic acid (CH3COOH) and sodium hydrogen carbonate (NaHCO3) is: CH3COOH + NaHCO3 -> CH3COONa + H2O + CO2 This reaction produces sodium acetate (CH3COONa), water (H2O), and carbon dioxide (CO2).
The complete molecular equation for the reaction between acetic acid (CH3COOH) and sodium hydroxide (NaOH) is: CH3COOH (aq) + NaOH (aq) -> CH3COONa (aq) + H2O (l)
There is no reaction between these two substances because an exchange of positive ions wouldn't result in higher product stability. Make sure your not confusing acetic with ascetic.
Hydrochloric acid (HCl) reacts with acetic acid (CH3COOH) to form water (H2O) and the salt sodium acetate (CH3COONa). The balanced chemical equation for this reaction is: HCl + CH3COOH → H2O + CH3COONa
ch3coona+FECL2
Formula: CH3COONa
It is sodium acetate anhydrous.