i think you mean Ca + AgNO3
Cu + AgNO3 --> Ag + Cu(NO3)2See formation of silver crystalshttp://www.youtube.com/watch?v=rgYhkVy5cBU
The equation is CaCl2 (aq) + 2 AgNO3 (aq) -> 2 AgCl (s) + Ca(NO3)2 (aq).
The chemical formula for silver nitrate is AgNO3.
To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. From this, you can calculate the mass of silver (Ag) in AgNO3, which is 107.87 g/mol. Therefore, the mass of silver in 3.4g of AgNO3 is (107.87/169.87) * 3.4g.
To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of silver nitrate (AgNO3). The molar mass of AgNO3 is 169.87 g/mol. Since the molar ratio of Ag to AgNO3 is 1:1, the mass of silver in 3.4g of AgNO3 would be 3.4g * (1/169.87) ≈ 0.02g.
2AgNO3 + CaSO4 ------> Ag2SO4 + Ca(NO3)2
The chemical reaction is:CaCl2 + 2 AgNO3 = 2 AgCl(s) + Ca(NO3)2The precipitate is silver chloride.
She was very spontaneous in her life, going wherever her whims might take her. The spontaneous reaction of sodium and water can be very dangerous.
Cu + AgNO3 --> Ag + Cu(NO3)2See formation of silver crystalshttp://www.youtube.com/watch?v=rgYhkVy5cBU
The equation is CaCl2 (aq) + 2 AgNO3 (aq) -> 2 AgCl (s) + Ca(NO3)2 (aq).
The chemical formula for silver nitrate is AgNO3.
The chemical formula for silver nitrate is AgNO3.
The reaction is:2 AgNO3 + CaCl2 = 2 AgCl(s) + Ca(NO3)2
To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. From this, you can calculate the mass of silver (Ag) in AgNO3, which is 107.87 g/mol. Therefore, the mass of silver in 3.4g of AgNO3 is (107.87/169.87) * 3.4g.
To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of silver nitrate (AgNO3). The molar mass of AgNO3 is 169.87 g/mol. Since the molar ratio of Ag to AgNO3 is 1:1, the mass of silver in 3.4g of AgNO3 would be 3.4g * (1/169.87) ≈ 0.02g.
AgNO3 powder is white but a little grey solid.
To find the number of moles, you need to divide the given mass (85 grams) by the molar mass of AgNO3 (169.87 g/mol). 85 grams of AgNO3 represents 0.500 moles.