Yes, FeI2 (Iron(II) iodide) is soluble in water.
The formula for iron iodide is FeI2. It consists of one iron (Fe) atom and two iodine (I) atoms.
The chemical formula for the compound formed from iron (II) and iodine is FeI2. Iron (II) has a +2 charge, and iodine has a -1 charge, so the correct formula involves two iodine atoms for every iron atom to balance the charges.
FeI2 is Iron (II) iodide, an ionic compound composed of iron with a +2 charge and iodide with a -1 charge.
The ionic compound for FeI2 is iron(II) iodide. It is formed by the combination of the metal ion Fe2+ and the nonmetal ion I-.
soluble in water.
FeI2
The formula for iron iodide is FeI2. It consists of one iron (Fe) atom and two iodine (I) atoms.
The chemical formula for iron(II) iodide is FeI2. It consists of one iron (Fe) ion with a +2 charge and two iodine (I) ions with a -1 charge each.
Iron(II) Iodide = FeI2 Iron(III) Iodide = FeI3
Iron II iodide
Formula: FeI2
The cation FeI2 does not exist on its own. Iron typically forms cations with a 2+ charge, like Fe2+, but it would not typically bond with two iodine atoms in this manner.
Iron(II) iodide = FeI2 Iron(III) iodide = FeI3
Ferrous iodide or iron II iodide is a salt with the formula FeI2, It is a compound of iron and iodine.
Lithium carbonate + Iron(II) iodide ----> Lithium iodide + Iron(II) carbonateLi2CO3 + FeI2 ----> 2 LiI + FeCO3
The chemical formula for the compound formed from iron (II) and iodine is FeI2. Iron (II) has a +2 charge, and iodine has a -1 charge, so the correct formula involves two iodine atoms for every iron atom to balance the charges.
FeI2 is Iron (II) iodide, an ionic compound composed of iron with a +2 charge and iodide with a -1 charge.