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Magnesium bromide, MgBr2, is not an acid. It is a salt.

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8y ago

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What is the fourmla for Mangnesium bromine?

MgBr


(a) Magnesium metal is placed into hydrobromic acid solution forming hydrogen gas and aqueous magnesium bromide.?

When magnesium metal is added to hydrobromic acid (HBr), a chemical reaction occurs, producing hydrogen gas (H₂) and aqueous magnesium bromide (MgBr₂). The magnesium displaces the hydrogen ions in the acid, resulting in the release of hydrogen gas as bubbles. The balanced chemical equation for this reaction is: Mg(s) + 2 HBr(aq) → H₂(g) + MgBr₂(aq). This reaction is exothermic and demonstrates the reactivity of magnesium with acids.


What is the correct chemical formula for magnesuim bromide?

MgBr MgBr2


Is MgBr a base?

MgBr is not a base, but rather a salt. It is composed of magnesium ion (Mg2+) and bromide ion (Br-). Bases typically contain hydroxide ions (OH-) and can accept protons to form water.


What is phenyl magnesium bromide?

it has phenyl group to which Mgbr attached at first position


What are the reactants for mgbr2?

The reactants for magnesium bromide (MgBr₂) are magnesium (Mg) and bromine (Br₂). In the reaction, one magnesium atom reacts with two bromine atoms to form magnesium bromide. The balanced chemical equation for the reaction is: [ \text{Mg} + \text{Br}_2 \rightarrow \text{MgBr}_2 ]


Which is the cation in mgbr2?

In the compound MgBr₂, the cation is magnesium (Mg²⁺). Magnesium donates two electrons to achieve a stable electron configuration, resulting in a positive charge. The anions in this compound are bromide ions (Br⁻), which balance the charge of the cation. Thus, MgBr₂ is composed of one magnesium cation and two bromide anions.


What is the correct name for the ionic compound Mg Br?

The correct name for the ionic compound MgBr is magnesium bromide.


What type of chemical reaction is MgBr plus F?

MgBr2 + F2 --> MgF2 + Br2 is a single replacement or single displacement reaction.


In the reaction Mg(s) plus Br2(l) MgBr2(s) what should be the coefficient for Br2?

In the reaction ( \text{Mg}(s) + \text{Br}_2(l) \rightarrow \text{MgBr}_2(s) ), the coefficient for ( \text{Br}_2 ) should be 1. This is because one magnesium atom reacts with one molecule of bromine to produce one formula unit of magnesium bromide, ( \text{MgBr}_2 ). Thus, the balanced equation is ( 1 \text{Mg}(s) + 1 \text{Br}_2(l) \rightarrow 1 \text{MgBr}_2(s) ).


In a reaction between MgCOËÄ and NHËÅBr the new magnesium compound formed would be?

In a reaction between MgCOËÄ and NHËÅBr the new magnesium compound formed would be MgBr2


When 8.95g of hydrated magnesium bromide is heated 2.03g of water is driven off What is the empirical Formula?

To find the empirical formula of hydrated magnesium bromide, we first determine the moles of magnesium (Mg), bromine (Br), and water (H₂O) after heating. The mass of anhydrous magnesium bromide is 8.95g - 2.03g = 6.92g. The moles of water lost (2.03g) is calculated as 2.03g / 18.02g/mol = 0.112 moles. Assuming magnesium bromide has the formula MgBr₂, we find the moles of Mg and Br in the remaining mass, leading to an empirical formula of MgBr₂·xH₂O, where x is determined by the ratio of moles of water to moles of MgBr₂.