negative
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∙ 8y agoThe reaction is 2NH₃(g) → N₂(g) + 3H₂(g), and since the number of moles of gas decreases from 2 moles to 4 moles, the entropy change is negative.
Since the balanced chemical equation for the Haber process is N₂ + 3H₂ → 2NH₃, the ratio of hydrogen to ammonia is 3:2. Therefore, 18 liters of hydrogen were used to produce 12 liters of ammonia.
For the reaction N₂ + 3H₂ → 2NH₃, the mole ratio of hydrogen gas to nitrogen gas is 3:1. Since 6 liters of hydrogen gas is used, you would need 2 liters of nitrogen gas at STP for this reaction according to the stoichiometry of the reaction.
The decomposition reaction of Al₂O₃·3H₂O is: 2Al₂O₃·3H₂O → 4Al(OH)₃ + 3H₂O. This reaction involves breaking down the hydrated aluminum oxide into aluminum hydroxide and water through the loss of water molecules.
3H is probably the most common. Technically 31H (the 3 and the 1 should actually be "stacked", but HTML doesn't really allow that) is correct as well, though the 1 is redundant (the H already tells you it has 1 proton). Since T is not used as a symbol for any other element, you'll occasionally see that as well. However, it's not "official".
To calculate the mass of ammonia formed, first write out the balanced chemical equation for the reaction between nitrogen and hydrogen to form ammonia: N₂ + 3H₂ → 2NH₃ Next, calculate the moles of nitrogen in 3.80 g using the molar mass of nitrogen (N₂). Then use the mole ratio from the balanced equation to determine the moles of ammonia formed. Finally, convert the moles of ammonia to grams using the molar mass of ammonia (NH₃) to find the mass formed.
simplify both sides of the equation: 1/3h+(-4)(2/3h)+(-4)(-3)=2/3h+-6 ~ distribute that 1/3h+-8/3h+12=2/3h+-6 (1/3h+-8/3h)+(12)=2/3h-6 ~ combine like terms for this -7/3h+12=2/3h-6 -7/3h+12=2/3h-6 subtract 2/3h from both sides: -7/3h+12-_2/3h=_2/3h-6-2/3h -3h+12=6 subtract 12 from both sides: -3h+12-12=-6-12 -3h=-18 divide both sides by -3 -3h/-3=-18/-3 h=6
3h+13 = 7 3h = 7-13 3h = -6 h = -2
Since the balanced chemical equation for the Haber process is N₂ + 3H₂ → 2NH₃, the ratio of hydrogen to ammonia is 3:2. Therefore, 18 liters of hydrogen were used to produce 12 liters of ammonia.
h = -5 8h - 10h = 3h + 25 -2h = 3h + 25 -2h - 3h = 3h - 3h + 25 -5h = 25 h = -5 CHECK: 8(-5) - 10(-5) = 3(-5) + 25 -40 - -50 = -15 + 25 -40 + 50 = 10 10 = 10 CORRECT
8h - 10h = 3h + 25-2h = 3h + 25-5h = 25-h = 5h = -5
3h + 20 - h + 5 = 2h + 25
- 3h - 2h + 6h + 9 = h + 9
For the reaction N₂ + 3H₂ → 2NH₃, the mole ratio of hydrogen gas to nitrogen gas is 3:1. Since 6 liters of hydrogen gas is used, you would need 2 liters of nitrogen gas at STP for this reaction according to the stoichiometry of the reaction.
The balanced equation for nitrogen (N₂) reacting with hydrogen (H₂) to form ammonia (NH₃) is: N₂ + 3H₂ -> 2NH₃
The value of 4g - 3h can't be determined since we are not given the value of g and h. The value of 4g - 3h is actually itself without the known values for g and h.
Monday-morning 2h evening 3h Tuesday-3h 2h Wednsday-1/2h 3/2h thursday-3h 2h Friday-2h 3h Saturday-3h 3h She would usually do alot of sprinting leading up to the games and she would do alot of technique to make her swim faster. She is a very competitive swimmer with alot of courage for her and her teammate's. She has a good hart and one day i would really like to meet her.
-9h-6+12h+40 = 22 3h+34 = 22 3h = 22-34 3h = -12 h = -4