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It is ionic, containing the two ions ammonium (NH4+) and bicarbonate (HCO3-).

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9y ago

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What is the ionic compounds of ammonium carbonate?

(NH4)2CO3----------------------Ammonium carbonate


Is ammonium cyanide an ionic or molecular?

Ammonium cyanide is an ionic compound, as it is formed from the combination of the ammonium cation (NH4+) and the cyanide anion (CN-), which are held together by ionic bonds.


What type of bond is present in the compound ammonium carbonate (NH32CO3)?

Ionic bond. Ammonium carbonate, NH4)2CO3, contains ionic bonds between the ammonium ion (NH4+) and the carbonate ion (CO3^2-).


Is NH4Br ionic or molecular?

Ammonium bromide is an ionic salt.


Is lithium carbonate molecular?

No, it is ionic.


What is the name for Ionic compound of (NH4)2CO3?

ammonium carbonate


Is ammonium phosphate ionic or molecular?

Ammonium phosphate is an ionic compound. It is formed through the combination of the ammonium ion (NH4+) and the phosphate ion (PO43-), which are both charged species that form an ionic bond.


Is NH4SO3 ionic or molecular?

It is a liquid so is molecular all the ionic compounds are solids.


What is the formula for ionic compound ammonium carbonate?

The formula for ammonium carbonate is (NH4)2CO3. It consists of two ammonium ions (NH4+) and one carbonate ion (CO3^2-) combined in the ratio of 2:1.


What is the formula of the ionic compounds of ammonium carbonate?

There is only one anhydrous ammonium carbonate, and it has the formula (NH4)2CO3. The questioner may be interested also in ammonium hydrogen carbonate, which has the formula NH4HCO3.


Is NH4Br is ionic or molecular?

NH4Br is an ionic compound. It is made up of ammonium (NH4+) and bromide (Br-) ions, which are held together by ionic bonds.


What is the formula for the compound NH4 and CO3?

The compound NH4CO3 is formed from the ammonium ion (NH4+) and the carbonate ion (CO3^2-). The chemical formula for ammonium carbonate is (NH4)2CO3, indicating the presence of two ammonium ions for each carbonate ion in the compound.