CF3Cl is a polar molecule. There are three C-F polar bond and and C-Cl polar bond. The bond dipoles do not cancel out and hence the compound is a polar molcule.
CF3Cl is a polar molecule. There are 3 C-F polar bond and 1 C-Cl polar bond. Since the difference in electronegative between C and F is not the same as that of C and Cl, therefore their bond polarities are not the same which results in the compound is a polar molcule.
For C2F3Cl3: 23 kg contains 3 kg of chlorine: (3 atoms of Cl per molecule) x (molar mass of Cl / molar mass of C2F3Cl3) x 23 kg. For CF3Cl: 6 kg of chlorine: (1 atom of Cl per molecule) x (molar mass of Cl / molar mass of CF3Cl) x 23 kg.
Vanillin is polar because it has polar functional groups such as hydroxyl and carbonyl groups. These functional groups create uneven distribution of charge within the molecule, making it polar overall.
SBr2 is a polar molecule. This is because the S-Br bonds are polar due to the difference in electronegativity between sulfur and bromine. Additionally, the shape of the molecule is angular, which results in an uneven distribution of electron density, making it polar overall.
It is a polar molecule and has polar bonds.
CF3Cl is a polar molecule. There are 3 C-F polar bond and 1 C-Cl polar bond. Since the difference in electronegative between C and F is not the same as that of C and Cl, therefore their bond polarities are not the same which results in the compound is a polar molcule.
For C2F3Cl3: 23 kg contains 3 kg of chlorine: (3 atoms of Cl per molecule) x (molar mass of Cl / molar mass of C2F3Cl3) x 23 kg. For CF3Cl: 6 kg of chlorine: (1 atom of Cl per molecule) x (molar mass of Cl / molar mass of CF3Cl) x 23 kg.
It is a tetrahedral. When making a Lewis structure, you will see 4 effective bonds. Then use a VESPR chart, and you will find it is a tetrahedral.
To determine the amount of chlorine in each compound, we first need to find the molar mass of each compound. The molar mass of C2F3Cl3 is 187.38 g/mol, and the molar mass of CF3Cl is 104.46 g/mol. Next, we calculate the mass percentage of chlorine in each compound by dividing the molar mass of chlorine by the total molar mass of the compound and multiplying by 100. For C2F3Cl3, the mass percentage of chlorine is 106.47 g/mol / 187.38 g/mol * 100 = 56.81%. For CF3Cl, the mass percentage of chlorine is 35.45 g/mol / 104.46 g/mol * 100 = 33.94%. Finally, we calculate the amount of chlorine in 22 kg of each compound by multiplying the mass percentage of chlorine by the total mass of the compound. For C2F3Cl3, the amount of chlorine is 22 kg * 56.81% = 12.49 kg. For CF3Cl, the amount of chlorine is 22 kg * 33.94% = 7.47 kg.
No its not polar
Polar contains polar. Non-polar contains nothing.
ClO4 is polar.
Nonpolar
Polar Polar
polar
IOF5 is polar - O has a double bond
Polar