Gold is a metal and so its bonding is via 'Sea of Electrons'.
This is not perfectly ionic nor perfectly covalent. Rather, the valence electrons are delocalised and moving within atomic orbitals of all immediate neighbouring atoms...
The chemical formula for gold (III) sulfide is Au2S3.
Sc2S3 is an ionic compound. It is composed of Scandium(III) ions (Sc^3+) and sulfide ions (S^2-), where the metal (Sc) loses electrons to form cations and the nonmetal (S) gains electrons to form anions.
The systematic name of this compound is Gold(III) Phosphate.
The chemical formula Cr2S3 is for dichromium trisulfide.
Iron (III) phosphate is an ionic compound. Iron (III) has a charge of +3, while phosphate has a charge of -3, resulting in a transfer of electrons and the formation of ionic bonds between the iron and phosphate ions.
Cr2S3 can be broken down. You know that when combined, the charges will flip and go to subscript. That means that it broken down, it is Cr^3 x S^2. Cr^3 is the transition metal, Chromium III. The S stand for Sulfur. So the answer is Chromium (III) Sulfide
The chemical formula for gold (III) sulfide is Au2S3.
Sc2S3 is an ionic compound. It is composed of Scandium(III) ions (Sc^3+) and sulfide ions (S^2-), where the metal (Sc) loses electrons to form cations and the nonmetal (S) gains electrons to form anions.
The chemical formula of gold(III) sulfide is Au2S3.
The systematic name of this compound is Gold(III) Phosphate.
The chemical formula Cr2S3 is for dichromium trisulfide.
Iron (III) phosphate is an ionic compound. Iron (III) has a charge of +3, while phosphate has a charge of -3, resulting in a transfer of electrons and the formation of ionic bonds between the iron and phosphate ions.
SbBr3 is Antimony (III) Bromide. It is an ionic compound.
Iron(III) chloride is an ionic compound.
Only the sulfide Ni3S2 - trinickel disulfide is known.
The chemical compound P2O2 does not exist. IF it could it would almost certainly be covalently bonded.
Electronegativity Fe = 1.83; O = 3.44 3.44 - 1.83 = 1.61 Since the electronegativity difference is 1.61 the bond is polar covalent 0 - 0.4 = Pure Covalent Bond 0.41 - 1.7 = Polar Covalent Bond 1.7 + = Ionic Bond