yes
The ability of an atom to borrow or lend electrons is determined by its electronegativity. Atoms with higher electronegativity tend to attract electrons towards themselves, while atoms with lower electronegativity are more likely to donate electrons. This tendency influences how atoms form chemical bonds with each other.
Firstly I would like to correct you on your grammar. The question should in fact ask 'which' element gains 5 electrons. The question is also flawed form the start because more than one element gains 5 electrons. All elements in group 3 of the Periodic Table have 5 spaces in the outer shell. All elements want to feel complete, and the maximum amount of elements on the outer shell is 8. Therefore 3 + 5 = 8. So hey presto this is my answer to you. ~K :)
Oxygen can lend two electrons to form a stable compound. Oxygen typically forms bonds by accepting two electrons to complete its outer shell and achieve a stable electron configuration.
That isn't necessarily true. The Halogens (group 17) follow what you said, but the Alkali metals (group 1) don't. As you go down the column, the elements get more reactive for group 1; Lithium is the least reactive and Francium (speculated) is the most reactive. On the other hand, as you down the Halogens, they do get less reactive. Astatine (speculated) is the least reactive while Fluorine is the most reactive element of them all. Hope that clears up things!
Nitrogen, with an atomic number of 7, has 5 electrons in its outer shell. It can lend or borrow a maximum of 3 electrons to achieve a stable octet configuration, like the noble gas neon. This allows nitrogen to form compounds such as ammonia (NH3) and ammonium (NH4+).
The ability of an atom to borrow or lend electrons is determined by its electronegativity. Atoms with higher electronegativity tend to attract electrons towards themselves, while atoms with lower electronegativity are more likely to donate electrons. This tendency influences how atoms form chemical bonds with each other.
2 because it has two outer shell electrons out of 8 (relevant rule only for the first 20 elements)
Firstly I would like to correct you on your grammar. The question should in fact ask 'which' element gains 5 electrons. The question is also flawed form the start because more than one element gains 5 electrons. All elements in group 3 of the Periodic Table have 5 spaces in the outer shell. All elements want to feel complete, and the maximum amount of elements on the outer shell is 8. Therefore 3 + 5 = 8. So hey presto this is my answer to you. ~K :)
Oxygen can lend two electrons to form a stable compound. Oxygen typically forms bonds by accepting two electrons to complete its outer shell and achieve a stable electron configuration.
That isn't necessarily true. The Halogens (group 17) follow what you said, but the Alkali metals (group 1) don't. As you go down the column, the elements get more reactive for group 1; Lithium is the least reactive and Francium (speculated) is the most reactive. On the other hand, as you down the Halogens, they do get less reactive. Astatine (speculated) is the least reactive while Fluorine is the most reactive element of them all. Hope that clears up things!
In theory 2 but in practice this has never been found. Helium is extremely stable and holds on to its electrons and does not share or "lend" them.
Magnesium tends to lend 2 electrons to achieve a stable electron configuration. Magnesium's electron configuration is [Ne] 3s^2, so by donating 2 electrons, it achieves a full outer shell and becomes a stable Mg^2+ ion.
2
2
Nitrogen, with an atomic number of 7, has 5 electrons in its outer shell. It can lend or borrow a maximum of 3 electrons to achieve a stable octet configuration, like the noble gas neon. This allows nitrogen to form compounds such as ammonia (NH3) and ammonium (NH4+).
Francium is an alkali metal that will lend electrons in an ionic compound.
Bromine can both lend and accept electrons, depending on the chemical reaction it is involved in. As a halogen, bromine typically accepts an electron to complete its octet and achieve a stable electron configuration.