The electron configuration Kr 5s2 4d10 5p5 is not valid. This configuration violates the Aufbau principle, which states that electrons fill orbitals starting with the lowest energy levels first. In this case, the 5s orbital should be filled before the 4d orbital. The correct electron configuration for a neutral krypton atom is Kr 5s2 4d10 5p6.
No, the electron configuration is incorrect. The correct electron configuration for an element with 52 electrons would be Kr 5s2 4d10 5p6.
It is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5.
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5
The unabbreviated electron configuration of iodine is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5.
The unabbreviated electron configuration for iodine is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5.
No, the electron configuration is incorrect. The correct electron configuration for an element with 52 electrons would be Kr 5s2 4d10 5p6.
It is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5.
1s22s22p63s23p64s2 3d104p65s24d105p5
The notation Ar 5s2 4d10 5p5 represents the electron configuration of the element arsenic (As), which has an atomic number of 33. This notation indicates that arsenic has 33 electrons distributed among its electron shells. The "Ar" in the notation represents the electron configuration of the noble gas argon, whose electron configuration is [Ne] 3s2 3p6, and serves as a shorthand way to denote the core electrons of the atom. The 5s2 4d10 5p5 portion specifies the distribution of the valence electrons in the outermost energy levels of the arsenic atom.
long hand: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5 short hand: [Kr] 5s2 4d10 5p5 *remember the number after the letter is written as an exponent*
(Kr)5s2 4d10 5p5
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6
The unabbreviated electron configuration for iodine is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5.
The unabbreviated electron configuration of iodine is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5.
Since it has a -1 charge, it must have 1 more electrons than in the ground state, making the ground state[Kr]5s2 4d10 5p4. This looks like Te (tellurium).