its always zero.
The charge of the polyatomic ion is occasionally included in the chemical formula for a compound containing it. This charge is never used in a binary ionic compound because binary compounds involve only two elements with differing charges, while polyatomic ions already contain multiple elements and an overall charge.
Zero. A compound will never have a net ionic charge.
The electronic configuration of F is [He] 2s2 2p5. An F atom needs just one more electron in its 2p shell to form the stable noble gas configuration. In gaining a single electron an F atom incurs a -1 negative charge. Thus, the charge on F ion is -1. The chemical formula for the F ion is F-.one negative
Formulas for compounds do not include oxidation numbers because these numbers are specific to an individual atom within a compound, and the compound as a whole remains neutral. Including oxidation numbers in the formula would imply a charge on the compound, which is not accurate for neutral compounds. The formula provides the ratio of atoms in the compound, while oxidation numbers are used to determine how electrons are distributed in a chemical species.
No, the empirical formula represents the simplest whole-number ratio of atoms in a compound, while the molecular formula shows the actual number of each element present in a compound. Therefore, the empirical formula cannot be triple the molecular formula.
The charge of the polyatomic ion is occasionally included in the chemical formula for a compound containing it. This charge is never used in a binary ionic compound because binary compounds involve only two elements with differing charges, while polyatomic ions already contain multiple elements and an overall charge.
Zero. A compound will never have a net ionic charge.
The electronic configuration of F is [He] 2s2 2p5. An F atom needs just one more electron in its 2p shell to form the stable noble gas configuration. In gaining a single electron an F atom incurs a -1 negative charge. Thus, the charge on F ion is -1. The chemical formula for the F ion is F-.one negative
Formulas for compounds do not include oxidation numbers because these numbers are specific to an individual atom within a compound, and the compound as a whole remains neutral. Including oxidation numbers in the formula would imply a charge on the compound, which is not accurate for neutral compounds. The formula provides the ratio of atoms in the compound, while oxidation numbers are used to determine how electrons are distributed in a chemical species.
No, the empirical formula represents the simplest whole-number ratio of atoms in a compound, while the molecular formula shows the actual number of each element present in a compound. Therefore, the empirical formula cannot be triple the molecular formula.
It would be a compound. An element's symbol never has more than three letters and never has more than one uppercase letter. Note, though that no compound with this formula exists. You must remember your subscripts. The correct formula is CaMg(CO3)2, the formula for the mineral dolomite.
I never heard about such a compound. If this exists, then it will be N3F4. By the way, check if you did not mean Dinitrogen tetrafluoride, as I don't know about trinitrogen tetrafluoride.
I never heard about such a compound. If this exists, then it will be N3F4. By the way, check if you did not mean Dinitrogen tetrafluoride, as I don't know about trinitrogen tetrafluoride.
An Oxygen atom would never contain 10 electrons on its own. It would have a maximum of 8 electrons at one time, unless the "oxygen atom" you are referring to is in fact an oxygen ION, in which case the charge would be -2. However, an oxygen ion can never be "by itself". It must be bonded with either itself as a diatomic or with another element as a compound.
By definition, it will always be an element, never a compound.
Compound or not, never separate a subject from its predicate with a comma.
Iodous acid is the chemical compound with the formula HIO2. Its' salts are named iodites; these are exceedingly unstable and have been observed but never isolated. They will rapidly break apart into iodine and iodates (the salt of iodic acid).