Yes, copper reacts with dilute sulfuric acid (H2SO4) to form copper sulfate (CuSO4) and release hydrogen gas (H2). This is a redox reaction.
When dilute sulphuric acid is added to copper oxide, a chemical reaction occurs, resulting in the formation of copper sulfate and water. The reaction can be represented by the equation: CuO + H2SO4 → CuSO4 + H2O.
The reaction between potassium iodide (KI) and dilute sulfuric acid (H2SO4) can be represented by the following equation: 2KI + H2SO4 -> 2KHSO4 + HI
The reaction is the following: H2SO4 + 2NaOH = Na2SO4 + 2H2O
The balanced chemical equation for the reaction between copper(II) oxide (CuO) and sulfuric acid (H2SO4) is: CuO + H2SO4 → CuSO4 + H2O
The precipitate formed when dilute sulfuric acid is added to copper(II) carbonate is copper(II) sulfate. The reaction can be represented as follows: CuCO3 + H2SO4 -> CuSO4 + H2O + CO2
When dilute sulphuric acid is added to copper oxide, a chemical reaction occurs, resulting in the formation of copper sulfate and water. The reaction can be represented by the equation: CuO + H2SO4 → CuSO4 + H2O.
The reaction between potassium iodide (KI) and dilute sulfuric acid (H2SO4) can be represented by the following equation: 2KI + H2SO4 -> 2KHSO4 + HI
The reaction is the following: H2SO4 + 2NaOH = Na2SO4 + 2H2O
The balanced chemical equation for the reaction between copper(II) oxide (CuO) and sulfuric acid (H2SO4) is: CuO + H2SO4 → CuSO4 + H2O
The precipitate formed when dilute sulfuric acid is added to copper(II) carbonate is copper(II) sulfate. The reaction can be represented as follows: CuCO3 + H2SO4 -> CuSO4 + H2O + CO2
The reaction between copper oxide (CuO) and sulfuric acid (H2SO4) produces copper sulfate (CuSO4) and water (H2O). The balanced chemical equation for this reaction is: CuO + H2SO4 -> CuSO4 + H2O
No, there is no reaction between copper & H2SO4 because according to reactivity series of metal hydrogen is more reactive than copper. Hence copper does not displace hydrogen from sulphuric acid..
CuCO3 + H2SO4 = CuSO4 + H2O + CO2 Its already balanced
The reaction between zinc and dilute sulfuric acid can be represented by the equation: Zn + H2SO4 -> ZnSO4 + H2. In this reaction, zinc reacts with sulfuric acid to produce zinc sulfate and hydrogen gas.
Let's see! CuO + H2SO4 --> CuSO4 + H2O ======================== This reaction is what I think would theoretically happen here; a salt, copper sulfate, and water produced.
Copper does not react with hot concentrated sulfuric acid due to its passivating oxide layer that prevents further reaction. The reaction between copper and sulfuric acid mainly occurs with dilute sulfuric acid, producing copper(II) sulfate and sulfur dioxide gas.
the reaction between cupperous oxide and sulphuric acid will give you a product of copper sulphate and water which is CuSO4 and H2o. I think this is correct product obtained as far as I know and this is a important chemical reation which is frequently udes in many industrial productions.