No, first xenon is an element, and so cannot be polar.
Second, it is monatomic, and a single atom cannot be polar.
Non-polar because Iodine is evenly 'distributed' or the molecule's angles are 180 degrees, and since there is equal pull from each iodine, and no lone pairs, the answer is nonpolar.
It will be weakly polar as a neutral compound, due to the presence of 1 unshared pair of electrons around the central xenon atom. (Additionally, the relatively large number of electrons in this compound will yield temporary dipoles in the form of dispersion forces.) If it's an ion, then I would need to know its charge. If its charge is +2 (meaning it has lost 2 electrons,) then that ion would be non-polar.
Xe (xenon) is a noble gas and is nonpolar because it has a symmetrical electron distribution around the central xenon atom, resulting in no net dipole moment.
The fluoride XeF3 is not known; the other xenon fluorides are nonpolar.
XeF2O is a polar molecule. This is because of the presence of lone pairs on the central xenon atom, causing an uneven distribution of electron density. This leads to a net dipole moment, making the molecule polar.
Non-polar because Iodine is evenly 'distributed' or the molecule's angles are 180 degrees, and since there is equal pull from each iodine, and no lone pairs, the answer is nonpolar.
XeCl2 (xenon dichloride) is a polar molecule. Although the individual Xe-Cl bonds are polar due to the difference in electronegativity between xenon and chlorine, the molecule has a bent geometry, which results in an unequal distribution of charge. This asymmetry leads to a net dipole moment, making XeCl2 polar.
No. Carbon tetrafuoride is a non polar molecule but with polar covalents bonds. the polar covalent bonds sort of cancel each other out on each opposite side (because of it's symmetry) making it non polar overall. (CF4 is tetrahedral)
It will be weakly polar as a neutral compound, due to the presence of 1 unshared pair of electrons around the central xenon atom. (Additionally, the relatively large number of electrons in this compound will yield temporary dipoles in the form of dispersion forces.) If it's an ion, then I would need to know its charge. If its charge is +2 (meaning it has lost 2 electrons,) then that ion would be non-polar.
Xe (xenon) is a noble gas and is nonpolar because it has a symmetrical electron distribution around the central xenon atom, resulting in no net dipole moment.
The fluoride XeF3 is not known; the other xenon fluorides are nonpolar.
XeF2O is a polar molecule. This is because of the presence of lone pairs on the central xenon atom, causing an uneven distribution of electron density. This leads to a net dipole moment, making the molecule polar.
The common intermolecular force between xenon and methanol is London dispersion forces. Xenon is a noble gas with temporary fluctuations in electron distribution, while methanol has a polar OH group that can induce temporary dipoles in nearby xenon molecules, leading to weak attractive forces.
XeF5+
The geometry of XeO3 is trigonal pyramid with an unsymmetric charge distribution. Therefore this molecule is polar. (This came from my chemistry book)
When you mix fluorine with xenon, the fluorine can react with xenon to form xenon fluorides, such as xenon tetrafluoride (XeF4) or xenon hexafluoride (XeF6). These xenon fluorides are generally unstable and highly reactive compounds.
Xenon is a noble gas. I would think any compounds would be hard to make with using Xenon.