KOH + HClO4 -> KClO4 + H2O
The balanced chemical equation for the reaction between HClO4 and KOH is HClO4 + KOH → KClO4 + H2O. By using the stoichiometry of the reaction, you can calculate the moles of HClO4 reacted with KOH. Then, use the remaining volume of KOH solution added to calculate the final H3O+ concentration in the solution.
To solve this problem, you first need to determine the moles of KOH present in the 30.0 mL sample. Then calculate the moles of HClO4 added after 39.9 mL. Based on these concentrations, determine the excess and limiting reagents to find the resulting pH. Consider the reaction that occurs between KOH and HClO4, and use the stoichiometry to calculate the amount of products formed. Finally, calculate the pH using the concentration of the resulting solution.
Balanced :2 K + 2 H2O ----> 2 KOH + H2
HClO4 is the strong acid known as perchloric acid.
This compound, HCLO4, is perchloric acid.
The balanced chemical equation for the reaction between HClO4 and KOH is HClO4 + KOH → KClO4 + H2O. By using the stoichiometry of the reaction, you can calculate the moles of HClO4 reacted with KOH. Then, use the remaining volume of KOH solution added to calculate the final H3O+ concentration in the solution.
The balanced chemical equation for the reaction between perchloric acid (HClO4) and potassium hydroxide (KOH) to form water (H2O) and potassium perchlorate (KClO4) is: HClO4 + KOH → H2O + KClO4
To solve this problem, you first need to determine the moles of KOH present in the 30.0 mL sample. Then calculate the moles of HClO4 added after 39.9 mL. Based on these concentrations, determine the excess and limiting reagents to find the resulting pH. Consider the reaction that occurs between KOH and HClO4, and use the stoichiometry to calculate the amount of products formed. Finally, calculate the pH using the concentration of the resulting solution.
Some caustic bases: NaOH, KOH, Ca(OH)2 Some caustic acids: HCl, HClO4, HNO3 (Caustic usually refers to alkaline materials, not acidic ones)
Balanced :2 K + 2 H2O ----> 2 KOH + H2
HClO4 is the strong acid known as perchloric acid.
This compound, HCLO4, is perchloric acid.
25 milliliters of the solution has . 037 moles of H2SO4. The neutralization reaction is H2SO4 + 2 KOH yields 2 H2O + K2SO4. So, . 074 moles of KOH are required. This equals 2. 71 mL of solution.
The compound with the formula HClO4 is called perchloric acid.
The chemical formula for Chloric Acid is HCIO3
The acid formed when HClO4 dissociates in water is called perchloric acid.
A substance that yields an anion plus the hydroxyl ion in water is a strong base. Examples include sodium hydroxide (NaOH) and potassium hydroxide (KOH) which dissociate completely in water to produce hydroxide ions.