MGS04 7H2O is Magnesium Sulfate . It is a heptahydrate.
Epsom Salts
The hydrate MgSO4 7H20 is magnesium sulfate heptahydrate.
Magnesium Sulfate (Forgot the 7H2O)
magnesium sulfate penta hydride
If the MgSO4 is the only oxygen containing compound in the salt, there must be four moles of oxygen atoms, and the number of atoms in 4 moles is 4 multiplied by Avogadro's number or about 2.409 X 1024 atoms.
Component Stock Solution mL Stock Solution/1L2M KNO3 202g/L 2.52M Ca(NO3)2 x 4H2O 236g/0.5L 2.5Iron (Sprint 138 iron chelate) 15g/L 1.52M MgSO4 x 7H2O 493g/L 11M NH4NO3 80g/L 1Minors: 1H3BO3 2.86g/LMnCl2 x 4H2O 1.81g/LZnSO4 x 7H2O 0.22g/LCuSO4 0.051g/LH3MoO4 x H2O or 0.09g/LNa2MoO4 x 2H2O 0.12g/L1M KH2PO4 (pH to 6.0 136g/L 0.5with 3M KOH)1) Make up stock solutions and store in separate bottles with appropriate label.2) Add each component to 800mL deionized water then fill to 1L.3) After the solution is mixed, it is ready to water plants.
The compound NiSO4 7H2O is magnesium sulfate heptahydrate. It is a type of inorganic salt that is commonly known as Epsom salt.
1 Gram is equal to 1000 milligrams so 25 Grams is equal to 25,000 grams
osmotic pressure=CRT x i 25 C to Kelvin = 298K 0.318atm= 0.010 M x 0.08206 x 298 K answer= 1.30
Oxygen is a chemical element with the symbol O and atomic number of 8. Its percentage composition in the compound NiSO4 x 7H2O is 31.3%.
2 NaOH + MgSO4-----Mg(OH)2+Na2SO4 1 MOLE OF MgSO4 produce one mole of Mg(OH)2 SO 1 MWT OF MgSO4 PRODUCE1MWT OF Mg(OH)2 HENCE 120 GM MgSO4 PRODUCE 58 gm OF Mg(OH)2 and so on if x gm of MgSO4 PRODUCE y gm OF Mg(OH)2 x=(120*y)/58 ---- ----
6. 1 x Mg, 1 x S, 4 x O
If the MgSO4 is the only oxygen containing compound in the salt, there must be four moles of oxygen atoms, and the number of atoms in 4 moles is 4 multiplied by Avogadro's number or about 2.409 X 1024 atoms.
Component Stock Solution mL Stock Solution/1L2M KNO3 202g/L 2.52M Ca(NO3)2 x 4H2O 236g/0.5L 2.5Iron (Sprint 138 iron chelate) 15g/L 1.52M MgSO4 x 7H2O 493g/L 11M NH4NO3 80g/L 1Minors: 1H3BO3 2.86g/LMnCl2 x 4H2O 1.81g/LZnSO4 x 7H2O 0.22g/LCuSO4 0.051g/LH3MoO4 x H2O or 0.09g/LNa2MoO4 x 2H2O 0.12g/L1M KH2PO4 (pH to 6.0 136g/L 0.5with 3M KOH)1) Make up stock solutions and store in separate bottles with appropriate label.2) Add each component to 800mL deionized water then fill to 1L.3) After the solution is mixed, it is ready to water plants.
1. Find the molar mass (MM) of the substances.MM FeSO4 = 151.91g+MM 7H2O = 126.11gMM FeSO4 x 7H2O = 278.02g2. Find the percent water of hydrate.Divide the mass of water by the mass of the hydrate; multiply result by 100%.126.11g278.02g x 100%Percent water of FeSO4 * 7H2O is 45.36%.Finding Molar Mass# atoms Element A x atomic mass Element A = Mass A# atoms Element B x atomic mass Element B = Mass B... etc.Add up all the mass values for the substance and you have the molar mass of the substance.
The compound NiSO4 7H2O is magnesium sulfate heptahydrate. It is a type of inorganic salt that is commonly known as Epsom salt.
molecular weight of NiSO4.7H2O is 1101.3 and it has 11 oxygens. So percentage of oxygen = (7 x 16) / 1101.3 = 112 / 1101.3 = 0.102 or 10.2%
120.4
1 Gram is equal to 1000 milligrams so 25 Grams is equal to 25,000 grams
osmotic pressure=CRT x i 25 C to Kelvin = 298K 0.318atm= 0.010 M x 0.08206 x 298 K answer= 1.30
The 'Ingredients' ; I think you mean the elemental atoms. Ferrous sulphate has the formula FeSO4 So the (ingredients) elementsal atoms are: - 1 x Fe ( Iron ; Latin Ferrum). 1 x S ( sulphur) 4 x O ( four atoms of oxygen).