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174 grams/mole. Looking at the Periodic Table: K is 39 grams/mole, S is 32 grams/mole, and O is 16 grams/mole.

So: 2*39 + 1*32 + 4*16 = 174.

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How many grams of K2SO4 would be needed to prepare 4.00 L of a 0.0510 M solution?

To calculate the grams of K2SO4 needed to prepare the solution, use the formula: (molarity) x (volume in liters) x (molar mass of K2SO4). First, calculate the moles of K2SO4 needed: 0.0510 mol/L x 4.00 L = 0.204 mol. Then, find the molar mass of K2SO4: 2*(39.10 g/mol) + 1*(32.07 g/mol) + 4*(16.00 g/mol) = 174.26 g/mol. Finally, multiply the moles by the molar mass: 0.204 mol x 174.26 g/mol ≈ 35.5 grams of K2SO4 are needed.


How many moles are there in 5 grams of potassium sulfate?

To find the number of moles in 5 grams of potassium sulfate (K2SO4), first calculate the molar mass of K2SO4 by adding the atomic masses of potassium (K), sulfur (S), and four oxygen (O) atoms. Then, divide the given mass (5 grams) by the molar mass of K2SO4 to get the number of moles.


How can one determine the molar mass from molality?

To determine the molar mass from molality, you can use the formula: Molar mass (molality x molar mass of solvent) / molality of solute. This equation helps you calculate the molar mass of a substance based on its molality in a solution.


What mass of potassium ions is present 25.0 mL of 0.50 M K2SO4 in grams?

To find the mass of potassium ions in 25.0 mL of 0.50 M K2SO4, first calculate the number of moles of K+ ions present. Since there are 2 K+ ions per K2SO4 unit, you have 0.50 moles/L * 0.025 L * 2 K+ ions/molecule. Finally, multiply the number of moles by the molar mass of potassium (39.10 g/mol) to find the mass in grams. The calculation would be: 0.50 mol/L * 0.025 L * 2 mol K+/mol K2SO4 * 39.10 g/mol K = 0.98 grams of potassium ions.


How do you find the percent of oxygen by mass in a compound?

To find the percent of oxygen by mass in a compound, you need to know the molar mass of the compound and the molar mass of oxygen. Divide the molar mass of oxygen by the molar mass of the compound and multiply by 100 to get the percentage.

Related Questions

Calculate the molar mass of K2SO4?

174.259 g/mol


How many moles of K2SO4 are in 15.0 grams of K2SO4?

To find the number of moles of K2SO4 in 15.0 grams, first calculate the molar mass of K2SO4 (K: 39.10 g/mol, S: 32.07 g/mol, O: 16.00 g/mol). Molar mass of K2SO4 = 2(39.10) + 32.07 + 4(16.00) = 174.26 g/mol Now, divide the given mass by the molar mass to find the number of moles: 15.0 g / 174.26 g/mol = 0.086 moles of K2SO4


How many grams of K2SO4 would be needed to prepare 4.00 L of a 0.0510 M solution?

To calculate the grams of K2SO4 needed to prepare the solution, use the formula: (molarity) x (volume in liters) x (molar mass of K2SO4). First, calculate the moles of K2SO4 needed: 0.0510 mol/L x 4.00 L = 0.204 mol. Then, find the molar mass of K2SO4: 2*(39.10 g/mol) + 1*(32.07 g/mol) + 4*(16.00 g/mol) = 174.26 g/mol. Finally, multiply the moles by the molar mass: 0.204 mol x 174.26 g/mol ≈ 35.5 grams of K2SO4 are needed.


How many moles are there in 5 grams of potassium sulfate?

To find the number of moles in 5 grams of potassium sulfate (K2SO4), first calculate the molar mass of K2SO4 by adding the atomic masses of potassium (K), sulfur (S), and four oxygen (O) atoms. Then, divide the given mass (5 grams) by the molar mass of K2SO4 to get the number of moles.


What mass of potassium ions is present 25.0 mL of 0.50 M K2SO4?

The Calculation25ml = 0.025dm30.5M = 0.5 moles per dm30.5 mol dm-3 x 0.025dm3 = 0.0125 moles of K2SO4Which equals 0.01125 moles of KThis in grams is 0.01125 x 39.098 (the molar mass of potassium) = 0.4398525g


What is the mass of 5 moles of Potassium Sulphate?

The molar mass of Potassium Sulphate (K2SO4) is 174.26 g/mol. Therefore, the mass of 5 moles of Potassium Sulphate would be 5 moles x 174.26 g/mol = 871.3 grams.


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