Well, when you mix NaOH with MgCl2, you get a fun little chemical reaction called a double displacement reaction. The sodium ions from NaOH swap places with the magnesium ions from MgCl2, forming magnesium hydroxide (Mg(OH)2) and sodium chloride (NaCl). It's like a chemistry party where everyone switches partners - just don't forget to balance your equation!
You have to realise that a drop from the burette for instance is insignificant, if you are dealing with at least 10ml solution which you usually deal with on a titration. If you don't want to regard it as insignificant, then if NaOH is in the burette, then the solution doesn't become more concentrated with NaOH because that drop escaped.
This solution contain 26,3 g NaOH.
4.00 grams of NaOH have been added to 2.00 liters of water. The molarity of this solution is?
The molarity of a NaOH solution is determined by the concentration of NaOH in moles per liter of solution. It is calculated by dividing the moles of NaOH by the volume of solution in liters. For example, a 0.1 M NaOH solution would contain 0.1 moles of NaOH per liter of solution.
The answer is 0,625 moles.
The net equation for the reaction between MgCl2 and NaOH is: MgCl2 + 2NaOH -> Mg(OH)2 + 2NaCl
You would need to add 18.75g of solid NaOH to the 750g of aqueous solution to obtain a 2.5% NaOH solution by mass.
75gm
The premise of this question is incorrect. When NaOH is added to water the hydroxide concentration increases. NaOH is a base. If a substance decreases hydroxide concentration it would be an acid.
You have to realise that a drop from the burette for instance is insignificant, if you are dealing with at least 10ml solution which you usually deal with on a titration. If you don't want to regard it as insignificant, then if NaOH is in the burette, then the solution doesn't become more concentrated with NaOH because that drop escaped.
To prepare a 0.1N solution of NaOH, dissolve 4g of NaOH pellets in enough distilled water to make 1 liter of solution. This will result in a solution with a concentration of 0.1N of NaOH.
Yes, you can make a 1N NaOH solution from a 0.1N NaOH solution by diluting it 10 times. For example, to make 1 liter of 1N NaOH solution, you would mix 100 ml of the 0.1N NaOH solution with 900 ml of water.
NaOH is added to water because it is highly exothermic, meaning it releases a significant amount of heat when it dissolves. Adding NaOH to water allows for better control of the heat generated and prevents splattering or boiling of the solution. Additionally, mixing NaOH with water allows the ions to disperse more evenly, resulting in a more homogeneous solution.
This solution contain 26,3 g NaOH.
4.00 grams of NaOH have been added to 2.00 liters of water. The molarity of this solution is?
The molarity of a NaOH solution is determined by the concentration of NaOH in moles per liter of solution. It is calculated by dividing the moles of NaOH by the volume of solution in liters. For example, a 0.1 M NaOH solution would contain 0.1 moles of NaOH per liter of solution.
560 g in 350 ml (But I am not sure if that large quantity of NaOH will dissolve in 350 ml of wate).