+2
1
Cl has an oxidation number of -1 because it is in the group 7a. -1*6 = -6 K has an oxidation number of +1 and there are three of them. -6+3+x = 0 The oxidation number of Co is +3.
+2 for Co, -2 for S
The oxidation number for Co in CoS is +2, a divalent cobalt cation, since the only anion formed from a single sulfur atom has a charge of -2.
The oxidation number is + for C and -2 for O.
+2
1
Cl has an oxidation number of -1 because it is in the group 7a. -1*6 = -6 K has an oxidation number of +1 and there are three of them. -6+3+x = 0 The oxidation number of Co is +3.
+2 for Co, -2 for S
The oxidation number for Co in CoS is +2, a divalent cobalt cation, since the only anion formed from a single sulfur atom has a charge of -2.
O.S. of Mn in Mn(CO)2 is 0.
Co = +2 oxidation C = +4 oxidation O = -2 oxidation
+4 oxygen has an oxidation of -2, so do 3 times -2=-6, i believe Ca is a +2 and you must get the numbers to equal 0. so the answer is a +4
In CoS, +2 for Co, -2 for S In Co2S3, +3 for Co, -2 for S (there is no compound by the formula, CoS3 as originally asked in the question)
CoCl3 is the chemical formula.Common oxidation states of cobalt include +2 and +3, so possible chlorides are: CoCl2 and CoCl3 , but the last one is rare.(CoF3 (Co(III)-fluoride) is a better possibillity to prove this oxidation state)Maximum oxidation state is +5, though Cobalt can easily 'coordinate' with in total 6 coordinative groups (=CG) and negative ions: Co(CG)4Cl2 (a coordinative group migh be a < -N| >-atom group of ammonia, ethylenediamine or haemoglobin)
nitrogen being more electronegative than carbon, the contribution of co-ordinate bond is neglected and carbon provides two electrons to nitrogen. so oxidation number of carbon in iso cyanide is +2