6. This is because it is a peroxide, with a structure Cr(O)(O2)2, where the nominal ligands are O2- (-2 ox.number in oxides) and O22- (-1 ox.number in peroxides) which gives the Cr an oxidation number of +6. It is sometimes called Chromium(VI) oxide peroxide.
6 for Chromium.
This is because it is a peroxide, with a butterfly structure Cr(O)(O2)2, where the nominal ligands are O2- (-2 oxidation number in oxides) and O22- (-1 oxidation number in peroxides) which gives the Cr an oxidation number of +6. It is sometimes called Chromium(VI) oxide peroxide.
+2 for Ca, +6 for Cr, -2 for each O
In CrBr (chromium monobromide) Cr would have an oxidation number of +1. This compound is not known perhaps you meant CrBr3, where chromium has an oxidation number of +3
Cr is a transition metal and has a variation of oxidation number from 0 in the elemental state to +6 in the dichromate ion.
In Cr2O72- chromium (Cr) has an oxidation number of 6+ while oxygen has an oxidation number of 2-.
As with any other element, the oxidation number of Cr depends on whether and how it is chemically bonded. The oxidation number of pure elements is arbitrarily defined to be 0. In compounds, Cr has oxidation numbers of +2, +3, and +6, depending on the compound.
Hi, CrO5 is a compound which has the structure which has peroxide linkage(O2 2-) as shown: Thus the oxidation number of Chromium can be calculated as : Let the oxidation number of Cr be x, then x-2-2(2)=0 x-2-4=0 x-6=0 thus x=+6
+2 for Ca, +6 for Cr, -2 for each O
In CrBr (chromium monobromide) Cr would have an oxidation number of +1. This compound is not known perhaps you meant CrBr3, where chromium has an oxidation number of +3
Cr is a transition metal and has a variation of oxidation number from 0 in the elemental state to +6 in the dichromate ion.
In Cr2O72- chromium (Cr) has an oxidation number of 6+ while oxygen has an oxidation number of 2-.
As with any other element, the oxidation number of Cr depends on whether and how it is chemically bonded. The oxidation number of pure elements is arbitrarily defined to be 0. In compounds, Cr has oxidation numbers of +2, +3, and +6, depending on the compound.
+6
+6
The answer is +6
+6 for Cr
O.S. of Cr = +6
6+