If you are referring to the nitrate ion, NO3-, the oxidation number of oxygen would be O2- and nitrogen would be N5+. If you are talking about nitrogen trioxide NO3, the oxidation number of oxygen would be O2- and nitrogen would be N6+.
Edit: Nitrogen trioxide does not exist in its free state.
The oxidation number for NO3 is -1. Since oxygen is usually assigned an oxidation number of -2 in compounds, the total oxidation number for the nitrate ion (NO3) must be -1 to account for the three oxygens.
+1 for Na +5 for N -2 for each O
In Ag NO3 the oxidation number of Ag (Silver) is 1+, the oxidation number of N (Nitrogen) is 5+, and the oxidation number of O (Oxygen) is 2-.
The sum of the oxidation numbers is zero for the compound.
The oxidation number of NO3- is -1. Each oxygen atom typically has an oxidation number of -2, totaling -6 for the three oxygen atoms. Since the overall charge of the nitrate ion is -1, the nitrogen atom must have an oxidation number of +5 to balance the charge.
The oxidation number for NO3 is -1. Since oxygen is usually assigned an oxidation number of -2 in compounds, the total oxidation number for the nitrate ion (NO3) must be -1 to account for the three oxygens.
+1 for Na +5 for N -2 for each O
In Ag NO3 the oxidation number of Ag (Silver) is 1+, the oxidation number of N (Nitrogen) is 5+, and the oxidation number of O (Oxygen) is 2-.
The sum of the oxidation numbers is zero for the compound.
The oxidation number of NO3- is -1. Each oxygen atom typically has an oxidation number of -2, totaling -6 for the three oxygen atoms. Since the overall charge of the nitrate ion is -1, the nitrogen atom must have an oxidation number of +5 to balance the charge.
The oxidation number of nitrogen in the nitrate ion NO3- is 5
+5. Oxygen is more electronegative than nitrogen and will exist in its most common -2 oxidation state. The three oxygen atoms in this ion therefore have a total charge of -6,requiring a formal charge on nitrogen of +5 to result in the charge -1 on the anion overall.
The oxidation number of Na in NaNO3 is +1, since Na typically has a +1 oxidation state in compounds. The oxidation number of N in NO3 is +5, since oxygen is usually assigned a -2 oxidation state and there are three oxygen atoms bonded to nitrogen in NO3.
Manganese III's oxidation number is +3 and Nitrate's oxidation number is -1. Because you want the oxidation numbers to add together to make zero, you'd need to use Nitrate three times in the compound: Mn(NO3)3
The oxidation number of chromium in CrNO3 is +3. This is because the overall charge of the nitrate ion (NO3-) is -1, and there are 3 nitrate ions in Cr(NO3)3. Therefore, the oxidation number of chromium must be +3 to balance out the -3 charge from the nitrate ions.
Calcium is a element. Nitrate is a ion. Calcium shows +2.
Na+ + NO3- --> NaNO3 The oxidation sum is zero for NaNO3.