Potassium iodide nitric acid

Answer 1

The equation for reaction between silver nitrate and sodium iodide in water solution is AgNO3 (aq) + NaI (aq) = NaNO3 (aq) + AgI (s).

Answer 2

reductor (I-) + oxidant (nitric) in dilute acid solution:

3I- + 2NO3- + 4H+ --> I3-(aq) + 2NO2(g) + 2H2O(l)

Answer 3

The reaction is:

KBr + AgNO3 = KNO3 + AgBr

The silver bromide is insoluble in water.

Answer 4

It would create silver iodide and potassium nitrate, the silver nitrate would precipitate and the potassium nitrate would remain in solution

Answer 5

A replacement reaction yielding silver iodide and potassium nitrate.

Answer 6

Potassium nitrate and a precipitate of Silver iodide

Answer 7

Silver iodate is prcipitated out . KIO3 + AgNO3 ----> AgIO3 + KNO3

Answer 8

= Potassium nitrate and Silver iodide

Answer 9

AgNO3 + KI = AgIs(precipitated ) + KNO3