Predict the bond angle for the molecule h2s?

Answer 1

Polar bonds occur when the atoms that are bonded have an unequal sharing of electrons, they are not polar but just do not share electrons equally.

Polar molecules occur when the molecule has polar bonds that are not equally distributed ie water is polar molecule because its polar bonds act at 104.5 degrees from one another whereas a molecule that was straight, 180 degrees, would not be polar due to the equal distribution of the bonds. A tetrahedral molecule has bonds going equally in four directions, therefore, no polar bond but ammonia which is trigonal pyramidal has three bonds acting downwards at 104 degrees from one another, therefore, it is a polar molecule.

Answer 2

It is relatively easy to predict which type of bonds will form. If the two atoms that are combining are a metal and a nonmetal, then you can assume that it will be an ionic bond. If the two combining atoms are both nonmetals, then you can assume it will be a covalent bond.

Answer 3

This is just one method but one I found to be most useful (not to mention straightforward):

1. Draw the Lewis structure of the molecule.

2. Determine how many atoms are bonded to the central atom.

3. Determine how many unshared electron (e-) pairs are on the central atom.

4. Identify the molecular geometry (shape) and the bond angle associated.

Below are some examples regarding molecular shapes with given bond angles (format is given below).

Shape: # atoms bonded to central atom, # unshared e- pairs on central atom, bond angle

Linear: 2 atoms, 0 unshared e- pairs, 180 degrees

Bent: 2 atoms, 2 unshared e- pairs, 104.5 degrees

Trigonal planar: 3 atoms, 0 unshared e- pairs, 120 degrees

Trigonal pyramid: 3 atoms, 1 unshared e- pairs, 107.3 degrees

Tetrahedral: 4 atoms, 0 unshared e- pairs, 109.5 degrees

For more information on Molecular Geometry and drawing Lewis Structures, please see related links.

Answer 4

Molecules H2O, H2Se, H2Te has two lone, non-bonding pairs of electrons. They originate from the atoms O, Se, Te which are in successive rows of the Periodic Table. As a result the electron pairs are attracted by the nuclei less and less strongly. As a consequence of this lower attraction the lone pairs occupy more space. This in turn causes the bond angle of the H's to become more acute. This reasoning is just one example of a semi-empirical bonding model called: Valence Shell Electron Pair Repulsion (VSEPR).

Answer 5

The bond angle in H2S is approximately 92 degrees. This deviation from the ideal 90 degrees for a tetrahedral arrangement is due to the lone pair electrons on the sulfur atom, which cause greater repulsion than bonding pairs.

Answer 6

This angle is 92,1 0.